Reputation: 1
Problem Description: (language is java)
Given an input array representing a preorder traversal of a binary search tree, output a postorder traversal of the BST.
Catch :
I have tried figuring it out for hours, but still have no clues.
The hardest part is without using the tree node struct.
Anyone have ideas?
Upvotes: 0
Views: 543
Reputation: 15911
here is a hint :
In preorder
traversal, the first element of the array is always going to be the root of the tree,
so if, NodeElemnts[]
is given array, then NodeElemnts[0]
will be the root of the trees
then, left node is located at 2n+1
and right node is located at 2n+2
, n
being the index of current array.
for Pre to Post :
[root][leftChild][rightChild]
(pre) -> [leftChild][rightChild][root]
(post) .....think BFS :)
Upvotes: 0