CODEWITHSUNDEEP
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Zolomon
Zolomon

Reputation: 9785

How to get the path of executed .jar file?

How do I get the path of a an executed .jar file, in Java?

I tried using System.getProperty("user.dir"); but this only gave me the current working directory which is wrong, I need the path to the directory, that the .jar file is located in, directly, not the "pwd".

Upvotes: 2

Views: 2653

Answers (3)

elou
elou

Reputation: 1282

Could you specify why you need the path?
If you need to access some property from the jar file you should have a look at ClassLoader.getSystemClassLoader();
don't forget that your classes are not necessary store in a jar file.


// if your config.ini file is in the com package.
URL url = getClass().getClassLoader().getResource("com/config.ini");
System.out.println("URL=" + url);

InputStream is = getClass().getClassLoader().getResourceAsStream("com/config.ini");
try {
    if (is != null) {
        BufferedReader br = new BufferedReader(new InputStreamReader(is));
        String line;
        while ((line = br.readLine()) != null) {
            System.out.println(line);
        }
    }
    else {
        System.out.println("resource not found.");
    }
}
catch (IOException e) {
    e.printStackTrace();
}

regards.

Upvotes: 2

PhiLho
PhiLho

Reputation: 41142

Perhaps java.class.path property?

If you know the name of your jar file, and if it is in the class path, you can find its path there, eg. with a little regex.

Upvotes: 0

Michal Ciechan
Michal Ciechan

Reputation: 13888

Taken From Java-Forumns:

        public static String getPathToJarfileDir(Object classToUse) {
        String url = classToUse.getClass().getResource("/" + classToUse.getClass().getName().replaceAll("\\.", "/") + ".class").toString();
        url = url.substring(4).replaceFirst("/[^/]+\\.jar!.*$", "/");
        try {
            File dir = new File(new URL(url).toURI());
            url = dir.getAbsolutePath();
        } catch (MalformedURLException mue) {
            url = null;
        } catch (URISyntaxException ue) {
            url = null;
        }
        return url;
      }

Upvotes: 0

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