manisha
manisha

Reputation: 695

How to get value present in a merged cell?

I want to get value of a merged cell that has range from D3 to H3 using openpyxl library. As per my understanding most libraries read data from 1st cell itself. Thus the merged content is present in it but I get a none value when I read it.

Following is my code:

wb = load_workbook(work_directory_path+'/outputs/report_vap.xlsx')
ws = wb.get_sheet_by_name("Summary")
suite_path = ws.cell('D3').value
if not isinstance(suite_path, unicode):
    value=unicode(suite_path)
value=value.encode('utf8')
print "Suite Location is "+value;

The output is :

Suite Location is None

The value in cell for D3 to H3 is :

c:\users\xyz\desktop\abc\c++\events\comevents

I even tried printing all the values in the sheet but except for integer values all values returned None.

Following is the changed code:

wb = load_workbook(work_directory_path+'/outputs/report_vap.xlsx')
ws = wb.get_sheet_by_name("Summary")
for row_index in range (ws.get_highest_row()):
    for col_index in range (ws.get_highest_column()):
        print ws.cell(row=row_index, column=col_index).value
suite_path = ws.cell('A11').value
print suite_path
if not isinstance(suite_path, unicode):
   value=unicode(suite_path)
value=value.encode('utf8')
print "Suite Location is "+value;

The output is:

None


None
None
None
None
None
None
None
None
None
None
None
None
None
None


None




None


None




None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None


None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
1
1
None
None
None
None
None
None
9
1106
None
None
None
None
None
None
10
1107
None
None
None
None
None
None
None
None
None
None
Suite Location is None
Suite Location is None
12

The Excel file has following content:

Project/module ID   Project/module  Build Analysis  Language    Compiler    Source File Source File

1_1 HTMLEdit.vcxproj    Success C++ Microsoft Visual Studio 2010 ( version 10.0 )   1   1

1_2 HTMLEdit.vcxproj    Success C++ Microsoft Visual Studio 2010 ( version 10.0 )   9   1106
Total                   10  1107

Upvotes: 13

Views: 21854

Answers (8)

nlaan
nlaan

Reputation: 67

I had to lookup many merged cells and it was quite slow. So I improved the performace with creating a dict before:

def collect_merge_dict(sheet):
    merge_dict = {}
    merge_ranges = sheet.merged_cells.ranges
    for index, merged_range in enumerate(merge_ranges):
        for col in range(merged_range.min_col, merged_range.max_col + 1):
            for row in range(merged_range.min_row, merged_range.max_row + 1):
                coord = (row, col)
                merge_dict[coord] = index

    return merge_dict

This is how I look up the cell values:

def get_merged_cell_value(sheet, merge_dict, cell):
    coord = (cell.row, cell.column)
    index = merge_dict.get(coord, -1)

    if index > -1:
        merged_range = sheet.merged_cells.ranges[index]
        return sheet.cell(merged_range.min_row, merged_range.min_col).value

    return cell.value

Upvotes: 0

sssbbbaaa
sssbbbaaa

Reputation: 244

Small update of @The Godfather's answer. Worked at openpyxl 3.0.7.

This modification is for the latest version of openpyxl. (The above answer was posted on 2015 and seems only for the older than 2.5.0)

import openpyxl


def getValueWithMergeLookup(sheet, cell):
    idx = cell.coordinate

    # for range_ in sheet.merged_cell_ranges:
    # 'merged_cell_ranges' has been deprecated
    # 'merged_cells.ranges' should be used instead
    for range_ in sheet.merged_cells.ranges:

        # merged_cells = list(openpyxl.utils.rows_from_range(range_))
        # 'rows_from_range' should take a 'str' type argument
        merged_cells = list(openpyxl.utils.rows_from_range(str(range_)))

        for row in merged_cells:
            if idx in row:
                # If this is a merged cell,
                # return  the first cell of the merge range

                # return sheet.cell(merged_cells[0][0]).value
                # You can just use 'sheet[<CELL ADDRESS>]' to take a cell
                # ex) sheet["A1"].value
                return sheet[merged_cells[0][0]].value

    # return sheet.cell(idx).value
    return sheet[idx].value

Upvotes: 1

Alex
Alex

Reputation: 488

One line to get value of a merged cell:

[r for r in sheet.merged_cells.ranges if cell.coordinate in r][0].start_cell.value

Upvotes: 1

Shady
Shady

Reputation: 246

I wrote this based on the latest source code from Openpyxl:

def getMergedCellVal(sheet, cell):
    rng = [s for s in sheet.merged_cells.ranges if cell.coordinate in s]
    return sheet.cell(rng[0].min_row, rng[0].min_col).value if len(rng)!=0 else cell.value

Upvotes: 17

Adanteh
Adanteh

Reputation: 51

from openpyxl import cell as xlcell, worksheet
def within_range(bounds: tuple, cell: xlcell) -> bool:
    column_start, row_start, column_end, row_end = bounds
    row = cell.row
    if row >= row_start and row <= row_end:
        column = cell.column
        if column >= column_start and column <= column_end:
            return True
    return False

def get_value_merged(sheet: worksheet, cell: xlcell) -> any:
    for merged in sheet.merged_cells:
        if within_range(merged.bounds, cell):
            return sheet.cell(merged.min_row, merged.min_col).value
    return cell.value

Should do it for current openpyxl version (2.6.3)

Upvotes: 3

RealZ
RealZ

Reputation: 1

from openpyxl import * 
from openpyxl.utils import *

    def getValueWithMergeLookup(sheet, cell):
        if cell == None or sheet == None:
            return None
        for irange in sheet.merged_cell_ranges:
            min_col, min_row, max_col, max_row =range_boundaries(irange)
            if cell.row in range(min_row,max_row+1) and column_index_from_string(cell.column) in range(min_col,max_col+1):
                return sheet.cell(None,min_row,min_col).value
        return cell.value

Upvotes: -1

okainov
okainov

Reputation: 4654

As soon as the only answer is incorrect (there is no more cells_from_range function in openpyxl) I suggest alternative way. I tried and it worked for my case:

Input is sheet and Cell. But if you need, it can be easily modified to accept string cell representation like 'A3'.

import openpyxl


def getValueWithMergeLookup(sheet, cell):
    idx = cell.coordinate
    for range_ in sheet.merged_cell_ranges:
        merged_cells = list(openpyxl.utils.rows_from_range(range_))
        for row in merged_cells:
            if idx in row:
                # If this is a merged cell,
                # return  the first cell of the merge range
                return sheet.cell(merged_cells[0][0]).value

    return sheet.cell(idx).value

Upvotes: 13

Tim Keating
Tim Keating

Reputation: 6641

Here's an approximation of the function that I use for this:

from openpyxl.cell import get_column_letter
from openpyxl.worksheet import cells_from_range

def getValueWithMergeLookup(sheet, col, row):
    idx = '{0}{1}'.format(get_column_letter(col), row)
    for range_ in sheet.merged_cell_ranges:
        cells = list(cells_from_range(range_))[0]
        if idx in cells:
            # If this is a merged cell, you can look up the value 
            # in the first cell of the merge range
            return sheet.cell(cells[0]).value

    return sheet.cell(row=row, column=col).value

The only really dicey bit there is where I extract the list of cells within the range to search against. That returns a generator, so I cast it to a list (because in doesn't work on generators, apparently), which yields a tuple containing a single list element, which I extract using the 0-index.

For my purposes, this is fast enough -- I use it by iterating the cells I want to test. If you wanted to make this more performant, it might be worthwhile to invert the loop, iterating the merge ranges as your outer loop, so you only have to do that conversion once.

Upvotes: 3

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