Reputation: 695
I want to get value of a merged cell that has range from D3 to H3 using openpyxl library. As per my understanding most libraries read data from 1st cell itself. Thus the merged content is present in it but I get a none value when I read it.
Following is my code:
wb = load_workbook(work_directory_path+'/outputs/report_vap.xlsx')
ws = wb.get_sheet_by_name("Summary")
suite_path = ws.cell('D3').value
if not isinstance(suite_path, unicode):
value=unicode(suite_path)
value=value.encode('utf8')
print "Suite Location is "+value;
The output is :
Suite Location is None
The value in cell for D3 to H3 is :
c:\users\xyz\desktop\abc\c++\events\comevents
I even tried printing all the values in the sheet but except for integer values all values returned None.
Following is the changed code:
wb = load_workbook(work_directory_path+'/outputs/report_vap.xlsx')
ws = wb.get_sheet_by_name("Summary")
for row_index in range (ws.get_highest_row()):
for col_index in range (ws.get_highest_column()):
print ws.cell(row=row_index, column=col_index).value
suite_path = ws.cell('A11').value
print suite_path
if not isinstance(suite_path, unicode):
value=unicode(suite_path)
value=value.encode('utf8')
print "Suite Location is "+value;
The output is:
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
None
1
1
None
None
None
None
None
None
9
1106
None
None
None
None
None
None
10
1107
None
None
None
None
None
None
None
None
None
None
Suite Location is None
Suite Location is None
12
The Excel file has following content:
Project/module ID Project/module Build Analysis Language Compiler Source File Source File
1_1 HTMLEdit.vcxproj Success C++ Microsoft Visual Studio 2010 ( version 10.0 ) 1 1
1_2 HTMLEdit.vcxproj Success C++ Microsoft Visual Studio 2010 ( version 10.0 ) 9 1106
Total 10 1107
Upvotes: 13
Views: 21854
Reputation: 67
I had to lookup many merged cells and it was quite slow. So I improved the performace with creating a dict before:
def collect_merge_dict(sheet):
merge_dict = {}
merge_ranges = sheet.merged_cells.ranges
for index, merged_range in enumerate(merge_ranges):
for col in range(merged_range.min_col, merged_range.max_col + 1):
for row in range(merged_range.min_row, merged_range.max_row + 1):
coord = (row, col)
merge_dict[coord] = index
return merge_dict
This is how I look up the cell values:
def get_merged_cell_value(sheet, merge_dict, cell):
coord = (cell.row, cell.column)
index = merge_dict.get(coord, -1)
if index > -1:
merged_range = sheet.merged_cells.ranges[index]
return sheet.cell(merged_range.min_row, merged_range.min_col).value
return cell.value
Upvotes: 0
Reputation: 244
Small update of @The Godfather's answer. Worked at openpyxl 3.0.7.
This modification is for the latest version of openpyxl. (The above answer was posted on 2015 and seems only for the older than 2.5.0)
import openpyxl
def getValueWithMergeLookup(sheet, cell):
idx = cell.coordinate
# for range_ in sheet.merged_cell_ranges:
# 'merged_cell_ranges' has been deprecated
# 'merged_cells.ranges' should be used instead
for range_ in sheet.merged_cells.ranges:
# merged_cells = list(openpyxl.utils.rows_from_range(range_))
# 'rows_from_range' should take a 'str' type argument
merged_cells = list(openpyxl.utils.rows_from_range(str(range_)))
for row in merged_cells:
if idx in row:
# If this is a merged cell,
# return the first cell of the merge range
# return sheet.cell(merged_cells[0][0]).value
# You can just use 'sheet[<CELL ADDRESS>]' to take a cell
# ex) sheet["A1"].value
return sheet[merged_cells[0][0]].value
# return sheet.cell(idx).value
return sheet[idx].value
Upvotes: 1
Reputation: 488
One line to get value of a merged cell:
[r for r in sheet.merged_cells.ranges if cell.coordinate in r][0].start_cell.value
Upvotes: 1
Reputation: 246
I wrote this based on the latest source code from Openpyxl:
def getMergedCellVal(sheet, cell):
rng = [s for s in sheet.merged_cells.ranges if cell.coordinate in s]
return sheet.cell(rng[0].min_row, rng[0].min_col).value if len(rng)!=0 else cell.value
Upvotes: 17
Reputation: 51
from openpyxl import cell as xlcell, worksheet
def within_range(bounds: tuple, cell: xlcell) -> bool:
column_start, row_start, column_end, row_end = bounds
row = cell.row
if row >= row_start and row <= row_end:
column = cell.column
if column >= column_start and column <= column_end:
return True
return False
def get_value_merged(sheet: worksheet, cell: xlcell) -> any:
for merged in sheet.merged_cells:
if within_range(merged.bounds, cell):
return sheet.cell(merged.min_row, merged.min_col).value
return cell.value
Should do it for current openpyxl version (2.6.3)
Upvotes: 3
Reputation: 1
from openpyxl import *
from openpyxl.utils import *
def getValueWithMergeLookup(sheet, cell):
if cell == None or sheet == None:
return None
for irange in sheet.merged_cell_ranges:
min_col, min_row, max_col, max_row =range_boundaries(irange)
if cell.row in range(min_row,max_row+1) and column_index_from_string(cell.column) in range(min_col,max_col+1):
return sheet.cell(None,min_row,min_col).value
return cell.value
Upvotes: -1
Reputation: 4654
As soon as the only answer is incorrect (there is no more cells_from_range function in openpyxl) I suggest alternative way. I tried and it worked for my case:
Input is sheet and Cell. But if you need, it can be easily modified to accept string cell representation like 'A3'.
import openpyxl
def getValueWithMergeLookup(sheet, cell):
idx = cell.coordinate
for range_ in sheet.merged_cell_ranges:
merged_cells = list(openpyxl.utils.rows_from_range(range_))
for row in merged_cells:
if idx in row:
# If this is a merged cell,
# return the first cell of the merge range
return sheet.cell(merged_cells[0][0]).value
return sheet.cell(idx).value
Upvotes: 13
Reputation: 6641
Here's an approximation of the function that I use for this:
from openpyxl.cell import get_column_letter
from openpyxl.worksheet import cells_from_range
def getValueWithMergeLookup(sheet, col, row):
idx = '{0}{1}'.format(get_column_letter(col), row)
for range_ in sheet.merged_cell_ranges:
cells = list(cells_from_range(range_))[0]
if idx in cells:
# If this is a merged cell, you can look up the value
# in the first cell of the merge range
return sheet.cell(cells[0]).value
return sheet.cell(row=row, column=col).value
The only really dicey bit there is where I extract the list of cells within the range to search against. That returns a generator, so I cast it to a list (because in
doesn't work on generators, apparently), which yields a tuple containing a single list element, which I extract using the 0-index.
For my purposes, this is fast enough -- I use it by iterating the cells I want to test. If you wanted to make this more performant, it might be worthwhile to invert the loop, iterating the merge ranges as your outer loop, so you only have to do that conversion once.
Upvotes: 3