CODEWITHSUNDEEP
ruby-on-railsrubyregex
tech_human
tech_human

Reputation: 7100

Getting string characters in an array

I have a string in ruby whose initial characters would be numbers and the last character would always be a letter. Some of the examples are: 2C, 1P, 45H, 135D.

I want to get an array which would have 2 objects, first would be the number and second would be the character.

Eg: for 2C, array would be [2, C]
    for 45H, array would be [45, H]
    for 135D, array would be [135, D]

I tried my_string[/(\d+)([A-Z])$/].split(//, 1), but it gives me an entire string in an array. Like ["2C"], ["45H"]

Am I missing something here?

Upvotes: 1

Views: 89

Answers (2)

Uri Agassi
Uri Agassi

Reputation: 37409

You can use scan:

'150D'.scan(/\d+|\w/)
# => ["150", "D"]

Upvotes: 1

Sam
Sam

Reputation: 20486

I had to do some quick Googling to see how to use Ruby's split, but here is how you want to do it:

print '2C'.split(/(?<=\d)(?=[A-Z])/);
// ["2", "C"]

The expression works by doing a lookbehind ((?<=...)) and a lookahead ((?=...)). This means we will match the spot that has a digit to the left and a letter to the right.

Upvotes: 4

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