CODEWITHSUNDEEP
jqueryajaxjquery-selectors
bateman_ap
bateman_ap

Reputation: 1921

JQuery can't call function on HTML placed using .load

I have come into a bit of a problem. I am dynamically updating dropdown lists using JQuery and PHP. I am using the following JQuery code to run a PHP page and insert the results into the page:

$("#booking-form-area").change(function()
  {
  ajax_availabletimes();
  })

function ajax_availabletimes(){
  var venue_val=$("#booking-form-venue").val();
  var people_val=$("#booking-form-people").val();
  $("#booking-form-time-select-ajax").load("/booking/times-dropdown.php", {venueUID : venue_val, people : people_val}, function(){
  })
}

In times-dropdown.php I am basically doing some lookups and returning some html in the form of:

<select class="small" id="booking-form-time-select"><option value="-1">Select Time...</option><option value="12:00">12:00pm</option><option value="12:30">12:30pm</option><option value="13:00">1:00pm</option></select>

This is put into the #booking-form-time-select-ajax div.

However if I now try selecting something in the dropdown here it should fire the function (this works before a dropdown has been selected and $("#booking-form-offer-select-ajax").load has replaced the code):

$("#booking-form-time-select").change(function()
  {
  ajax_offerdropdown();
  })

I can only presume once JQuery has replaced the code in booking-form-time-select then it can't use selectors? Any idea how to fix this? I have been reading up about $(data) function but it's quite confusing and not sure it is what I am looking for?

Upvotes: 0

Views: 731

Answers (4)

Luca Rocchi
Luca Rocchi

Reputation: 6464

as alternative why do not replace only the options while leaving intact the tag select ? i mean just return

Select Time...12:00pm12:30pm1:00pm

from php code and update the select options using $('#booking-form-time-select').html(options); this way your handler is preserved

Upvotes: 1

Quasipickle
Quasipickle

Reputation: 4498

The .change() listener is added at page load, so when you replace a DOM element, the attached .change() listener gets removed. Try using live(), which will automagically add the listener to any DOM elements that get added after initial page load.

Upvotes: 2

Pointy
Pointy

Reputation: 413709

Use "live"

 $("#booking-form-time-select").live('change', function() { ... });

Upvotes: 1

Nick Craver
Nick Craver

Reputation: 630389

Use .live() in this case:

$("#booking-form-time-select").live('change', function(){
  ajax_offerdropdown();
});

This puts an event listener up at the DOM level that won't get erased as the element is replaced.

Upvotes: 4

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