Reputation: 21
I want to ask about mysql query
I have table data like this
My data
`userid | time| date
609 | 07:56:31|2014-01-23
609 | 21:20:47|2014-01-23
609 | 17:25:27|2014-01-24
609 | 17:25:29|2014-01-24
609 | 17:13:54|2014-01-27
609 | 17:13:56|2014-01-27
609 | 07:55:09|2014-01-27`
I've tried various ways
but have not been successful
like
set @start='1900-01-01';
set @finish='2033-12-31';
SELECT data.userid,t.clock_out,data.date from data
inner join (select max(time)as clock_out,date,userid from data where time>='10:01' group by data.userid,tgl)t
on(data.date = t.date and data.userid=t.userid and t.clock_out=date.time)
rule
clock_in where time<='10:00' and clock_out time>'10:00',clock_in or clock_out can fill in the blank/empty,,the date for example 25 and 26 is not input data,but can be retrieved from variable @start='1900-01-01'and @finish='2033-12-31';
and result would be
userid|date |clock_in | clock_out
609 |2014-01-23 |07:56 |21:20
609 |2014-01-24 | |17:25
609 |2014-01-25 | |
609 |2014-01-26 | |
609 |2014-01-27 |07:55 |17:13
. Can someone help me....:( thanks.in advance....
Upvotes: 2
Views: 2190
Reputation: 39951
I think this is what you want, it isn't exactly as your answer but I think this is correct.
You need to join in a list of all unique dates for that user id and then use that list to group by and get min() and max() from time.
select t1.userid,
t2.date,
min(t1.time) as in_time,
max(t1.time) as out_time
from test t1
join (select distinct date from test where userid = 609) t2
where t1.date = t2.date
and userid = 609
group by t1.userid, t2.date;
I would also say that it seems far better to instead of a date and a time just store a datetime and then group by some function that selects the date-part.
http://sqlfiddle.com/#!2/7b8732/1
Upvotes: 1
Reputation: 2452
Have you tried GROUP_CONCAT?
SELECT user_id, date, GROUP_CONCAT(time) as in_out FROM data GROUP BY date ORDER BY date,time;
This isn't 100% what you need, but might be close enough?
Upvotes: 0