CODEWITHSUNDEEP
c++warnings
thundium
thundium

Reputation: 1063

How can I silence the "unused parameter" warning?

I am cleaning all the warning for given codes.(Which means I am not fully understand each line logic). "[-Wunused-parameter]" is enabled and shall not be turned off.

And for "unused parameter", we usually just use "_ _ attribute _ _((unused))".

While for following functions, I can't use that above trick.

void fun(int* a =0){
    ----variable ptr a is not used at all----
}

Any good idea to have a clean solution to remove the warning?

Upvotes: 2

Views: 388

Answers (1)

Mike Seymour
Mike Seymour

Reputation: 254471

This easiest way is not to name the parameter:

void fun(int* =0){
    //...
}

Upvotes: 5

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