CODEWITHSUNDEEP
java
Bhadresh
Bhadresh

Reputation: 15

Java String to Byte. Why does the value get changed?

I have the following method, where I am setting the value "9" in String. When I put this in byte and display the output then the value gets changed.

void method() {
    String s = "9";
    byte[] b = s.getBytes();
    System.out.println("Byte value is: " + byte[0]);
}

Output: 

Byte value is: 57

Here why is 9 getting converted to 57?

Upvotes: 0

Views: 235

Answers (4)

Srikanth Hugar
Srikanth Hugar

Reputation: 385

In above example you need to correct the compilation problems first: It should code should be like :

 System.out.println("Byte value is: " + b[0]);

And not 

 System.out.println("Byte value is: " + byte[0];

And regarding the output, You are assigning "9" as string and trying to fetch the byte[], basically getBytes encodes this String into a sequence of bytes using the platform's default charset, storing the result into a new byte array. hence your getting "57".

Upvotes: 0

MadukaJ
MadukaJ

Reputation: 761

when you trying to get byte value from character you get only ASCII value.

character '9' ASCII code is 57

Upvotes: 0

richardtz
richardtz

Reputation: 4993

57 is the ASCII code for the character '9'

Upvotes: 2

awksp
awksp

Reputation: 11867

Because the character '9' is ASCII value 57:

https://www.cs.cmu.edu/~pattis/15-1XX/common/handouts/ascii.html

ASCII character 9 would be a "tab" character

Upvotes: 3

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