Reputation: 59
So I have 3 Forms, lets call them Form1, Form2, and Form3. I have sent the IsMDIParent Property to true for Form1.
When I launch the app, It loads Form2 as an MDI Child using
Form2 frm = new Form2();
frm.MdiParent = this;
frm.Show();
And that works fine. What I then want to do is click a button withing the 2nd form that will close Form2 and open up Form3 as a child form of Form1.
I tried
SecondForm SecondFormMDI = new SecondForm();
SecondFormMDI.MdiParent = Form1;
SecondFormMDI.Show();
on the button click event in Form2, but it would not work.
Do I have to always launch a Child form from the parent form? and if so, how would i go about doing that when it is on the button click event on a child form?
Upvotes: 0
Views: 2567
Reputation: 51
ChildForm frmChild = new ChildForm();
frmChild.MdiParent = this.MdiParent;
frmChild.Dock = DockStyle.Fill();
frmChild.Show();
Upvotes: 0
Reputation: 2866
Just use this.MdiParent, instead of Form1, like
SecondForm SecondFormMDI = new SecondForm();
SecondFormMDI.MdiParent = this.MdiParent;
SecondFormMDI.Show();
Upvotes: 1
Reputation: 7
You could create a method in your MDIForm to open a childform:
public void OpenForm(Form form)
{
form.MdiParent = this;
form.Show();
}
When you want to open a new form in another form you do something like this (example in ChildFormOne with button):
private void btnOpenChildFormTwo_Click(object sender, EventArgs e)
{
((MDIForm)this.MdiParent).OpenForm(new ChildFormTwo());
this.Close();
}
Hope this helps.
Upvotes: 0
Reputation: 82474
You can set the MDIParent of any form in design time, why do it in run-time? Simply set the value of MDIParent property of Form2 and Form3 to Form1, and that's it.
Upvotes: 0