CODEWITHSUNDEEP
c#xmllinqms-word
Hugh Jones
Hugh Jones

Reputation: 2694

How to extract the names of all bookmarks in a Word Xml Document

I have a word Document in Xml format with multiple entries like so :

    <aml:annotation aml:id="0" w:type="Word.Bookmark.Start" w:name="CustomerName"/>

I want to retrieve a collection of these but cannot see how to get past

    foreach (XElement ann in doc.Root.Descendants(aml + "annotation"))

In other words I can get all annotations, but cannot see how to filter to just retrieve bookmarks. The namespaces aml and w are declared like this

    XNamespace w = "http://schemas.openxmlformats.org/wordprocessingml/2006/main";
    XNamespace aml = "http://schemas.microsoft.com/aml/2001/core";

Could someone give me a push ?

I resolved the issue as follows

        XNamespace w = doc.Root.GetNamespaceOfPrefix("w"); 
        XNamespace aml = doc.Root.GetNamespaceOfPrefix("aml");

        foreach (string bookm in doc.Descendants(aml + "annotation")
                                    .Where(e => e.Attributes(w + "type")
                                    .Any(a => a.Value == "Word.Bookmark.Start"))
                                    .Select(b => b.Attribute(w + "name").Value))
        {
             ...
        }

Upvotes: 0

Views: 932

Answers (2)

BigMan
BigMan

Reputation: 464

This solution is not for XML but maybe helps you. 

System.Collections.Generic.IEnumerable<BookmarkStart> BookMarks = wordDoc.MainDocumentPart.RootElement.Descendants<BookmarkStart>();
foreach (BookmarkStart current in BookMarks)
{
    //Do some...
}

Upvotes: 0

Sergey Berezovskiy
Sergey Berezovskiy

Reputation: 236308

var names = from a in doc.Root.Descendants(aml + "annotation"))
            where (string)a.Attribute(w + "type") == "Word.Bookmark.Start"
            select (string)a.Attribute(w + "name");

Lambda syntax:

doc.Root.Descendants(aml + "annotation")
        .Where(a => (string)a.Attribute(w + "type") == "Word.Bookmark.Start")
        .Select(a => (string)a.Attribute(w + "name"))

Upvotes: 1

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