Reputation: 45
I have two models with a many to many relationship (SQLAlchemy):
association_table = Table('association', Base.metadata,
Column('left_id', Integer, ForeignKey('left.id')),
Column('right_id', Integer, ForeignKey('right.id'))
)
class Parent(Base):
__tablename__ = 'left'
id = Column(Integer, primary_key=True)
children = relationship("Child",
secondary="association",
backref="parents")
class Child(Base):
__tablename__ = 'right'
id = Column(Integer, primary_key=True)
Get "all parents of one (second on the list) the child" I can that way:
parents = session.query(Parent).filter(Parent.children.any(id=2))
And how to get "all the children of a parent"?
Upvotes: 2
Views: 3543
Reputation: 76972
Any of the below should do:
# 1.
children = session.query(Child).filter(Child.parents.any(Parent.id==??))
# 2.
children = session.query(Child).join(Parent, Child.parents).filter(Parent.id == 99)
# 3.
my_parent = session.query(Parent).get(2)
children = session.query(Child).with_parent(my_parent).all()
Upvotes: 1