CODEWITHSUNDEEP
regextclexpect
Dinesh
Dinesh

Reputation: 16436

Regular expression in expect with tcl

I need to match the expect for the following output

1/ 5  SOMETEXT      Active

I am using the following code 

expect -re "1\/\s+(\d)\s+SOMETEXT\s+Active"
send "\r"
puts $expect_out(0,string)

Here, I am matching the digit '5' from the input text.

But, with this code, expect is not able to find the result from the input.

Upvotes: 1

Views: 411

Answers (2)

Donal Fellows
Donal Fellows

Reputation: 137767

You have a problem in this code; there are backslashes in there that need quoting so they go to the RE engine. Try one of these:

expect -re "1/\\s+(\\d)\\s+SOMETEXT\\s+Active"

expect -re {1/\s+(\d)\s+SOMETEXT\s+Active}

Note also that / is not special at all to Tcl's RE engine or to Tcl; it's just an ordinary character. You never need to quote it in itself (unlike with \ where you need to be careful).

Upvotes: 2

glenn jackman
glenn jackman

Reputation: 247162

You want expect_out(1,string) -- that is the 1st captured group
expect_out(0,string) contains the portion of the text that matches the regex

$ expect
expect1.1> spawn sh -c {echo '1/ 5  SOMETEXT      Active'}
spawn sh -c echo '1/ 5  SOMETEXT      Active'
4093
expect1.2> expect -re {1/\s+(\d+)\s+SOMETEXT\s+Active}
1/ 5  SOMETEXT      Active
expect1.3> puts $expect_out(1,string)
5
expect1.4> puts $expect_out(0,string)
1/ 5  SOMETEXT      Active

Upvotes: 1

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