Reputation: 935
Suppose, we've got a Go function, which is doing something with agruments, passed to them, e.g. it could fill the buffer, allocated in the C part and changing it and for example an integer argument, which is a size of read data. It works well with an integer one, but not with a "data part". Just see a code.
package main
/*
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <inttypes.h>
extern int some(uint8_t *, int *);
static int somewrap() {
uint8_t *i = malloc(16);
int A = 1;
int *x = &A;
some(i, x);
fprintf(stderr, "c.wrapper, i=%s, %p, x=%d, %p\n", i, i, *x, x);
return 0;
}
*/
import "C"
import "fmt"
import (
"unsafe"
)
//export some
func some(i *C.uint8_t, x *C.int) C.int {
fmt.Println("i:", i, &i, *i, "x:", x, &x, *x)
p := []byte("xxx")
i = (*C.uint8_t)(unsafe.Pointer(&p[0]))
*x = C.int(42)
fmt.Println("i:", i, &i, *i, "x:", x, &x, *x)
return C.int(0)
}
func main() {
C.somewrap()
}
As a result, we've got following:
i: 0x4303a40 0xc210000018 0 x: 0x7fff5fbff874 0xc210000020 1
i: 0xc210000038 0xc210000018 120 x: 0x7fff5fbff874 0xc210000020 42
c.wrapper, i=, 0x4303a40, x=42, 0x7fff5fbff874
As you can see, it works well for integer pointer, but not for uint8_t.
Upvotes: 2
Views: 1105
Reputation: 109357
You're re-assigning i
within some
to another address, not change the value at the given address (unless I'm misunderstanding what you're trying to accomplish)
*i = *(*C.uint8_t)(unsafe.Pointer(&p[0]))
Upvotes: 3