CODEWITHSUNDEEP
jaxbapache-camelmarshalling
Ya.
Ya.

Reputation: 2627

Camel cxf: how to marshal incoming message to XML?

I want to serialize the incoming message to XML. I'm starting from the camel-example-cxf-osgi example.

My Route:

JaxbDataFormat jaxb = new JaxbDataFormat();

from("cxf:bean:reportIncident")
 .convertBodyTo(InputReportIncident.class)
 .marshal(jaxb)
 .bean(new MyBean2())
 .transform(constant(ok));

But I'm getting error and I'm at a loss:

java.io.IOException: javax.xml.bind.JAXBException: class org.apache.camel.example.reportincident.InputReportIncident nor any of its super class is  known to this context.

Appreciate any help. Thx.

Upvotes: 0

Views: 3427

Answers (2)

Peter Keller
Peter Keller

Reputation: 7636

Alternatively to the solution of Daniel, you could use

final JAXBContext jaxbContext = JAXBContext.newInstance(InputReportIncident.class);
final DataFormat jaxb = new JaxbDataFormat(jaxbContext);

This comes in handy if there is no ObjectFactory class. See Jaxb: How do I generate ObjectFactory class? for more general information about this subject.

Upvotes: 2

Daniel
Daniel

Reputation: 2500

You need to point your to the package where you keep your jaxb classes, something like 

DataFormat jaxb = new JaxbDataFormat("com.acme.model");

The exception says that the jaxb context doesn't know how to marshal the class InputReportIncident.class.

Upvotes: 1

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