Reputation: 5568
I'm having a strange problem with Gulp. Here is my Gulp file:
var gulp = require('gulp');
var autoprefixer = require('gulp-autoprefixer');
var notify = require('gulp-notify');
var sass = require('gulp-ruby-sass');
gulp.task('default', function() {
gulp.run('main');
gulp.watch('sass/*.scss', function() {
gulp.run('main');
})
});
gulp.task('main', function() {
return gulp.src('sass/**/*.scss')
.pipe(sass())
.on('error', notify.onError(function(error) { return 'Error: ' + error.message; }))
// .pipe(autoprefixer('last 10 version'))
.pipe(gulp.dest('./css'))
.pipe(notify({ message: 'Your SASS has been auto-prefixed and minified.'}))
;
});
The script runs correctly the first time. But on second and subsequent runs of the same script (without Gulp having stopped running), it puts it in the SASS directory as a subitem of the .SCSS file. Any idea why this is happening. I'm not sure how to even debug.
Upvotes: 2
Views: 994
Reputation: 2957
Found the answer, the gulp.dest keeps the folder structure of gulp.src, to override you can set the base property of the src, this will exclude whatever folder the base is set to
example gulp.src('./sass/' + '**/*.scss', {base: 'sass'})
this now excludes sass from the destination, no longer appending sass to your gulp.dest
Upvotes: 1
Reputation: 4162
Try the following code.
It uses the correct syntax for gulp, replacing gulp.run()
with the supported function arguments.
var gulp = require('gulp');
var autoprefixer = require('gulp-autoprefixer');
var notify = require('gulp-notify');
var sass = require('gulp-ruby-sass');
gulp.task('main', function() {
return gulp.src('./sass/**/*.scss')
.pipe(sass())
.on('error', notify.onError(function(error) { return 'Error: ' + error.message; }))
.pipe(gulp.dest('./css'))
.pipe(notify({ message: 'Your SASS has been auto-prefixed and minified.'}));
});
gulp.watch('sass/*.scss', ['main']);
gulp.task('default', ['main']);
Upvotes: 1