CODEWITHSUNDEEP
bash
tlre0952b
tlre0952b

Reputation: 751

Console output suppressed. Why?

In my bash script I have a function that:

When I run the script from the terminal and the bash script reaches the statement of:

myExpectFunc
[further code...]

why is it that I can see the console output of the expect script, but if I do the following:

retVal=$(myExpectFunc)
[further code...]

there will be no console output? It is like it is suppressed until retVal has been assigned a value.

I'd like to keep local variables to functions and return the values of these variables as my return value for me to be able to case on. Of course if I don't declare local variables to the function the variable will be global and I can simply case on the global variable. But I'd rather not do this. So is there a way to be able to maintain the console output and assign the return value to retval?

Upvotes: 1

Views: 160

Answers (1)

John1024
John1024

Reputation: 113864

So is there a way to be able to maintain the console output and assign the return value to retval?

Yes. Use tee:

retVal=$(myExpectFunc | tee /dev/tty)

All of the standard output from myExpectFunc is sent to the standard input of tee. tee copies that to both to the file /dev/tty (which is your terminal) and to its own standard out (which is then captured by retVal).

Upvotes: 1

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