CODEWITHSUNDEEP
phparraysmultidimensional-array
Travis
Travis

Reputation: 2021

How to find every possible combination of an arbitrary number of arrays in PHP

I have an arbitrary number of nested arrays in php. For example:

Array
(
    [0] => Array
        (
            [0] => 36
            [0] => 2
            [0] => 9
        )

    [1] => Array
        (
            [0] => 95
            [1] => 21
            [2] => 102
            [3] => 38
        )

    [2] => Array
        (
            [0] => 3
            [1] => 5
        )

)

I want to find the most efficient way to combine all possible combinations of each of these nested arrays. I'd like to end up with something that looks like this...

Array
(
    [0] => "36,95,3"
    [1] => "36,95,5"
    [2] => "36,21,3"
    [3] => "36,21,5"

    etc...

)

The order the results are combined in is not important. That is to say, there is no difference between "3,95,36", "36,95,3", and "95,36,3". I would like to omit these redundant combinations.

Any suggestions on how to go about this would be much appreciated.

Thanks in advance,

Upvotes: 0

Views: 822

Answers (2)

Slava Nadvorny
Slava Nadvorny

Reputation: 151

General permutation solution for any number of groups (in Groovy to keep it simple). 

list = [["A", "B", "W"], ["C", "D"], ["X", "Y"]]

r = []
void p(List<List<String>> l, int n) {
    for(t in l[n]) {
        r[n] = t
        if (n < l.size() - 1) {
            p(l, n + 1)
        } else {
            println(r)
        }
    }
}

p(list, 0);

Upvotes: 0

Chirag Darji
Chirag Darji

Reputation: 11

<?php
$a = array("01", "02");
$b = array("white", "green");
$c = array("one", "two", "three");
$aG = array($a, $b, $c);
$codes = array();
$pos = 0;
generateCodes($aG);

function generateCodes($arr) {
    global $codes, $pos;
    if(count($arr)) {
    for($i=0; $i<count($arr[0]); $i++) {
        $tmp = $arr;
        $codes[$pos] = $arr[0][$i];
        $tarr = array_shift($tmp);
        $pos++;
        generateCodes($tmp);

    }
    } else {
    echo join(", ", $codes)."<br/>";
    }
    $pos--;
}
?>

Upvotes: 1

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