Reputation: 49
First, i have a code that i need to know if the user has clicked on one submit button, then, i need one function to enable another submit button that is disabled by disabled="disabled".
Here's my noob function (Needs improves, does not work). :
<script>
function EnableSend() {
if(document.getElementById("Submit_Facebook").click(); {
document.getElementById("submit").disabled = false; }
}
</script>
And now the code:
1 - Disabled Submit: (Will be enabled after user click on Submit_Facebook submit button).
<input id="submit" name="submit" type="submit" value="" disabled="disabled">
2 - Other submit that will make the disabled submit enabled.
<form method="post" class="button" action="<?=$PHP_SELF;?>"">
<input id="Submit_Facebook" name="Submit_Facebook" type="submit" value=""onclick="EnableSend()">
</form>
3 - Php part
<?php
if (isset($_POST['Submit_Facebook'])) {
echo "<script>alert('You now can proceed to step two.');</script>";
echo '<script type="text/javascript"language="javascript">window.open("#");</script>';
exit;
}?>
Well, my english is not that good, but if you guys need any detail just contact me, thanks for your attention.
Upvotes: 3
Views: 9007
Reputation: 11
You got to remove disabled
attribute from input.
Something like this:
var EnableSend = function(){
$( "#submit" ).removeAttr('disabled');
};
Upvotes: 1
Reputation: 25142
<input id="submit" name="submit" type="submit" value="send" disabled="disabled">
<input id="Submit_Facebook" name="Submit_Facebook" type="submit" value="" onclick="EnableSend();">
<script type="text/javascript">
function EnableSend() {
document.getElementById("submit").disabled = false;
}
</script>
Upvotes: 2