Reputation: 287
I'm working on following query:
INSERT INTO a (id, value) VALUES (_id, (SELECT value FROM b WHERE b.id = _id));
Table a: id, value (has a default value)
Table b: id, value
Table b does not contain all requested values. So the SELECT query sometimes returns 0 rows. In this case it should use the default value of a.value.
Is this somehow possible?
Upvotes: 3
Views: 5619
Reputation: 191
you can wrap the value in coalesce(max(value), default_value)
INSERT INTO a (id, value)
VALUES (_id, (SELECT coalesce(max(value), default_value)) FROM b WHERE b.id = _id));
Upvotes: 3
Reputation: 5669
The following query would work. First the max(value) is looked up from table b for _id. It would be either NULL or equal to b.value. If it is NULL (checked using the COALESCE function), then the default value of the value column of table a is set as the value.
The default value of the value column of table a is accessed using the DEFAULT function (please refer Reference 1).
INSERT INTO a
SELECT
_id,
COALESCE(max(value), (SELECT DEFAULT(value) FROM a LIMIT 1)) value
FROM b
WHERE id = _id;
Reference:
Upvotes: 0
Reputation: 86775
If MySQL follows other RDBMS behaviour, the default is only picked up when you don't even specify the field. This means that you need two different INSERT statements:
IF (EXISTS(SELECT * FROM b WHERE id = _id)) THEN
INSERT INTO a (id, value) SELECT _id, value FROM b WHERE id = _id;
ELSE
INSERT INTO a (id) SELECT _id;
END IF;
Or, possibly, something like this...
INSERT INTO a (id, value) SELECT _id, value FROM b WHERE id = _id;
IF ((SELECT ROW_COUNT()) = 0) THEN
INSERT INTO a (id) SELECT _id;
END IF;
Please note, this is conceptual. I've looked up the syntax for you, but I haven't tested it on MySQL.
Upvotes: 0