CODEWITHSUNDEEP
phpjavascriptjquerypost
user285969
user285969

Reputation:

How to pass variable from JavaScript to PHP using jQuery POST

I am passing the variable sessionnum from the following Javascript function in the page chat.php:

$(document).ready(function(){

        timestamp = 0;
        updateMsg();
        $("form#chatform").submit(function(){
            $.post("backend.php",{
                        message: $("#msg").val(),
                        name: author,
                        action: "postmsg",
                        time: timestamp,
                        tablename1: sessionnum
                    }, function(xml) {
                $("#msg").empty();

                addMessages(xml);

                document.forms['chatform'].reset()
                fixScroll();
            });
            return false;
        });
    });

To the following PHP function in backend.php:

if(@$action == "postmsg") {
    mysql_query("INSERT INTO `$tablename1` (`user`,`msg`,`time`)
                VALUES ('$name','$message',".time().")",$dbconn);
    mysql_query("DELETE FROM `$tablename1` WHERE id <= ".
                (mysql_insert_id($dbconn)-$store_num),$dbconn);
    }

$messages = mysql_query("SELECT user,msg
                         FROM `$tablename1`
                         WHERE time>$time
                         ORDER BY id ASC
                         LIMIT $display_num",$dbconn);

It only works when I hard-code an assignment such as $tablename1 = 100 in backend.php even though both the variable and its value are integers and the same value. This hack is not acceptable, as I actually have to pass the variable. Is there a bug in my code?

This code is adapted from http://articles.sitepoint.com/article/ajax-jquery/3

Thanks for any help POSTING the variable correctly with jQuery.

Upvotes: 0

Views: 5245

Answers (2)

cmptrgeekken
cmptrgeekken

Reputation: 8092

Try changing the POST variables to $_POST['variable_name']. You're using a syntax that relies on globals being registered as variables. This is a feature that is a) not enabled by default and b) poses a major security risk when it is enabled. Thus, try changing your server-side code to:

$action = $_POST['action'];
$tablename1 = mysql_real_escape_string($_POST['tablename1']);
$name = mysql_real_escape_string($_POST['name']);
$message = mysql_real_escape_string($_POST['message']);

if(@$action == "postmsg") {
    mysql_query("INSERT INTO `$tablename1` (`user`,`msg`,`time`)
                VALUES ('$name','$message',".time().")",$dbconn);
    mysql_query("DELETE FROM `$tablename1` WHERE id <= ".
                (mysql_insert_id($dbconn)-$store_num),$dbconn);
    }

$messages = mysql_query("SELECT user,msg
                         FROM `$tablename1`
                         WHERE time>$time
                         ORDER BY id ASC
                         LIMIT $display_num",$dbconn);

Note that, in order to prevent some SQL injections, the variables that you're using in your SQL queries (that the user can potentially change) have been escaped using mysql_real_escape_string.

Upvotes: 2

bdl
bdl

Reputation: 1502

It would appear as though you're relying on register_globals, and referencing what would be the POST variable in PHP, instead of referencing the $_POST superglobal index, e.g.

if ( $_POST['action'] == 'postmsg' ) {
    $name= mysql_real_escape_string( trim( $_POST['name'] ) );
    // query using $name reference
}

As an aside, you should really reconsider allowing the use of the tablename in the client side code.

Upvotes: 1

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