CODEWITHSUNDEEP
c#.netgenerics
Bob
Bob

Reputation: 4386

How can I get the name of a generic class programmatically?

I want to get the name of a class dynamically. I can use this: 

public void RequestData<TResult>()
{
     var myName = typeof(TResult).Name;
}

Which works fine e.g. if TResult is of type MyClass then myName would equal "MyClass"

But if TResult is of type

List<MyClass>

I still want myName to equal "MyClass" ... at the moment it will be "List`1"

So if TResult is going to be of type List how can I programmatically know that it's a List and then pick out the name of the type of this list?

Upvotes: 1

Views: 302

Answers (3)

Lee
Lee

Reputation: 144136

You can get the 'leftmost' inner generic type with

public static Type GetInnermost(Type t)
{
    while(t.IsGenericType)
    {
        t = t.GetGenericArguments()[0];
    }
    return t;
}

then you can do:

var myName = GetInnermost(typeof(TResult)).Name;

then e.g.

RequestData<List<IEnumerable<Task<IObserverable<string>>>();

will have a name of String.

Upvotes: 2

Felipe Oriani
Felipe Oriani

Reputation: 38608

You could use the GetGenericArguments method, which returns an array of Type objects that represent the type arguments of a generic type or the type parameters of a generic type definition. (MSDN).

For sample:

public void RequestData<TResult>()
{
     var myName = typeof(TResult).Name;
     var type = typeof(TResult)
     if (type.IsGenericType)
     {
         myName = type.GetGenericArguments().First().Name;
     }
}

Upvotes: 1

Tim S.
Tim S.

Reputation: 56536

That can be done with the help of a few methods on the Type.

public void RequestData<TResult>()
{
    Type type = typeof(TResult);
    string myName;
    if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(List<>))
    {
        myName = type.GetGenericArguments()[0].Name;
    }
    else
    {
        myName = typeof(TResult).Name;
    }
}

Upvotes: 3

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