CODEWITHSUNDEEP
regex
user3649739
user3649739

Reputation: 1869

Find a block of descriptive text inside html using regex

I'm trying to figure out how to use look-ahead to try to capture the descriptive text in an html page such as

<div class="itemBanner" style="float:left; padding:10px">
<div style="padding-right:5px; padding-bottom:5px">
<div class="itemBanner">
HTML Tags Stripper is designed to strip HTML tags from the text. It will also strip embedded JavaScript code, style information (style sheets), as well as code inside php/asp tags (&lt;?php ?&gt; &lt;%php ?&gt; &lt;% %&gt;). It will also replace sequence of new line characters (multiple) with only one. <b>Allow tags</b> feature is session sticky, i.e. it will remember allowed tags list, so you will have to type them only once.<p></p>You can either provide text in text area below, or enter URL of the web page. If URL provided then HTML Tags Stripper will visit web-page for its contents.<p></p>
<b>Known issues:</b><br />

I figured a regex that looks for a '>' followed by at least 150 characters before a '<' would do the trick.

The closest I've gotten so far is:

(([^.<]){1,500})<

Which still misses on things like periods and other characters before and after the string.

Upvotes: 0

Views: 83

Answers (1)

Kache
Kache

Reputation: 16687

Your regex will match anything that's neither "." nor "<" 1 to 500 times, then a "<".

Assuming you want to capture everything from the itemBanner div until the very next occurrence of a closing div, you can use these elements:

  • <div class="itemBanner"> - explicit match
  • () - parathentical wrap for referencing, e.g. match[1]
  • .*? - any length of characters, non-greedily (as few as possible)
  • <\/div> - explicit match, with escaped '/'

to form this Ruby regex:

item_banner_div_regex = /<div class="itemBanner">(.*?)<\/div>/
match = item_banner_div_regex.match(html)
inside_item_banner_div = match && match[1]

Note: The exact regex will depend on the implementation you're using.

Upvotes: 1

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