Is there analog of ".." for c++ namespaces?

Question

Hello I have the following structure in my code:

namespace ns
{
class A
{
  public:
    class Impl
    {
        public: static int x;
    };
    class B
    {
      public:
        class Impl
        {
          public:
            Impl(){printf("%d", ns::A::Impl::x);}
        };
    };
};
}

Is there a way to access that x property, using a relative, not the absolute path?

It would be more convenient, because, someday I could change the namespace name from ns to e.g. other, or put this entire file into some outer namespace.

Answer 1

There isn't an equivalent of "..", i.e. a way to specify "the enclosing namespace/class", but you can manually implement a similar thing:

class B
{
    typedef A parent;          // <---- add this

// ...

    printf("%d", parent::Impl::x);

In this particular situation it doesn't gain anything: this is just a more roundabout way of having A::Impl::x as Maxim suggested. But in general, if you have a more complicated hierarchy then this form may gain you some readability.

Answer 2

Is there a way to access that x property, using a relative, not the absolute path?

Symbols from the enclosing scope/namespace are accessible in the current scope/namespace.

ns::A::Impl::x could be shortened to A::Impl::x (can't omit A:: because you have two Impl).