Reputation: 739
I want to check if Enter key was pressed twice within 5 secs and perform some action. How can I check if the key was pressed once or twice within a given time and perform different actions.
Here is my code:
<h1 id="log">0</h1>
<br/>
<span id="enteredTime">0</span>
<script>
$(document).keypress(function(e) {
if(e.which == 13){
var element = $("#log");
var timeDifference = 0;
//Log the timestamp after pressing Enter
$("#enteredTime").text(new Date().getTime());
//Check if enter was pressed earlier
if ($("#enteredTime").text() !== "0") {
var now = new Date().getTime();
var previous = $("#enteredTime").text();
difference = now - previous;
}
//Check if enter was pressed only once within 5 secs or more
if(){
$("#log").text("Once");
$("#enteredTime").text("0");
//Check if enter was pressed twice in 5 secs
}else{
$("#log").text("Twice in less than 5 secs");
$("#enteredTime").text("0");
}
}
});
</script>
Thanks!
Upvotes: 2
Views: 1580
Reputation: 20626
Check your Updated Fiddle
var count = 0;
$(document).keypress(function(e) {
var element = $("#log");
var timeDifference = 0;
if(e.which == 13){
count++;
console.log('enter pressed'+count);
if(count == 1){
startTimer();
}
else{
checkCount();
}
//Log the timestamp after pressing Enter
$("#enteredTime").text(new Date().getTime());
if ($("#enteredTime").text() !== "0") {
var now = new Date().getTime();
var previous = $("#enteredTime").text();
difference = now - previous;
}
}
});
function startTimer(){
setTimeout(checkCount,5000);
}
function checkCount(){
if(count == 1){
$("#log").text("Once");
$("#enteredTime").text("0");
//Check if enter was pressed twice in 5 secs
}else{
$("#log").text("Twice in less than 5 secs");
$("#enteredTime").text("0");
}
}
startTimer()
starts counting on first enter press. And checkCount()
contains your condition after 5secs.
setTimeout() lets you attach an event which occurs after a specific timespan.
Upvotes: 0
Reputation: 30736
Bacon.js seems like a good tool to express this.
$(document).asEventStream('keypress')
.filter(function (x) {
return x.keyCode == 13;
})
.map(function () {
return new Date().getTime();
})
.slidingWindow(2, 1)
.map(function (x) {
return (x.length == 1 || x[1] - x[0] > 5000) ? 1 : 2;
})
.onValue(function (x) {
$("#log").text(x == 1 ? "Once" : "Twice in less than 5 secs");
});
Upvotes: 1
Reputation: 3663
here is my solutions, please check it if match your idea :)
(function($){
var element = $("#log");
var timeDifference = 0;
var count = 0;
$(document).keypress(function(e) {
if(e.which === 13){
//do what you want when enterpress 1st time
/*blah blah */
//after done 1st click
count++;
if(count === 2) {
//do what you want when enterpress 2nd time in 5 seconds
/* blah blah */
//after done
clearTimeout(watcher);
count = 0;
return;
}
//setTimeout to reset count if more than 5 seconds.
var watcher = setTimeout( function() {
count = 0;
},5000);
}
});
}(jQuery)
Upvotes: 0
Reputation: 4868
something like
var start=0;
$(document).keyup(function(e) {
if(e.keyCode == 13) {
elapsed = new Date().getTime();
if(elapsed-start<=5000){
//do something;
}
else{
//do something else;
}
start=elapsed;
}
});
Upvotes: 2
Reputation: 388316
Try a timer based solution like
var flag = false,
timer;
$(document).keypress(function (e) {
var element = $("#log");
var timeDifference = 0;
if (e.which == 13) {
if (flag) {
console.log('second');
clearTimeout(timer);
flag = false;
} else {
console.log('first');
flag = true;
timer = setTimeout(function () {
flag = false;
console.log('timeout')
}, 5000);
}
//Log the timestamp after pressing Enter
$("#enteredTime").text(new Date().getTime());
if ($("#enteredTime").text() !== "0") {
var now = new Date().getTime();
var previous = $("#enteredTime").text();
difference = now - previous;
}
}
});
Demo: Fiddle
Upvotes: 1