Reputation: 3897
I have jQuery AJAX function that returns HTML after querying a database. Depending on the result of the query, the function will either return HTML code or nothing (i.e. blank) as desired.
I need to conditionally check for when the data is blank.
$.ajax({
type:"POST",
url: "<?php echo admin_url('admin-ajax.php'); ?>",
data: associated_buildsorprojects_form,
success:function(data){
if(!data){
//if(data="undefined"){
//if(data==="undefined"){
//if(data==null){
//if(data.length == 0){
//if ( data.length != 0 ){
//if(data===0){
//if(data==="0"){
alert("Data: " + data);
}
},
error: function(errorThrown){
alert(errorThrown);
alert("There is an error with AJAX!");
}
});
I've tried a variety of conditions but none correctly check the data. Based on my findings, a blank alert message does not mean data is
If it's none of these things, how can I therefore conditionally check for the data that yields a blank alert message?
Upvotes: 67
Views: 270810
Reputation: 3897
The following correct answer was provided in the comment section of the question by Felix Kling:
if (!$.trim(data)){
alert("What follows is blank: " + data);
}
else{
alert("What follows is not blank: " + data);
}
Upvotes: 105
Reputation: 22395
//if(data="undefined"){
This is an assignment statement, not a comparison. Also, "undefined"
is a string, it's a property. Checking it is like this: if (data === undefined)
(no quotes, otherwise it's a string value)
If it's not defined, you may be returning an empty string. You could try checking for a falsy
value like if (!data)
as well
Upvotes: 30
Reputation: 397
$.ajax({
type:"POST",
url: "<?php echo admin_url('admin-ajax.php'); ?>",
data: associated_buildsorprojects_form,
success:function(data){
// do console.log(data);
console.log(data);
// you'll find that what exactly inside data
// I do not prefer alter(data); now because, it does not
// completes requirement all the time
// After that you can easily put if condition that you do not want like
// if(data != '')
// if(data == null)
// or whatever you want
},
error: function(errorThrown){
alert(errorThrown);
alert("There is an error with AJAX!");
}
});
Upvotes: 2
Reputation: 51
This worked form me.. PHP Code on page.php
$query_de="sql statements here";
$sql_de = sqlsrv_query($conn,$query_de);
if ($sql_de)
{
echo "SQLSuccess";
}
exit();
and then AJAX Code has bellow
jQuery.ajax({
url : "page.php",
type : "POST",
data : {
buttonsave : 1,
var1 : val1,
var2 : val2,
},
success:function(data)
{
if(jQuery.trim(data) === "SQLSuccess")
{
alert("Se agrego correctamente");
// alert(data);
} else { alert(data);}
},
error: function(error)
{
alert("Error AJAX not working: "+ error );
}
});
NOTE: the word 'SQLSuccess' must be received from PHP
Upvotes: 3