CODEWITHSUNDEEP
javascriptregex
Adrian Rosca
Adrian Rosca

Reputation: 7392

Extract doubles and integers from string with regex in javascript

When I try this:

"12.3 xxx4.56 23yyy".match(/\d+/ig)

I get this output:

["12", "3", "4", "56", "23"]

I would like this:

["12.3", "4.56", "23"]

What's the correct regex?

Upvotes: 1

Views: 153

Answers (2)

Dalorzo
Dalorzo

Reputation: 20014

How about this: 

"12.3 xxx4.56 23yyy".match(/([\d.]+)/g)

i seems to be unnecessary since you are only searching for number i case insensitive is unnecessary.

Upvotes: 1

Alexander R
Alexander R

Reputation: 2476

You can use an optional group in the regex to handle this case. Like so:

"12.3 xxx4.56 23yyy".match(/\d+(\.\d+)?/ig)
=> Array [ "12.3", "4.56", "23" ]

The (...)? syntax means that everything inside is optional - if present it will be matched, but if not it won't prevent a match. The ? alone could also be applied to a single term.

Upvotes: 1

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