CODEWITHSUNDEEP
django
user3675339
user3675339

Reputation: 3

Django Intro Tutorial - Invoke Python Shell

I am new to django and am starting to go through the documenation and the poll tutorial. Install etc has been no problem and I have gotten as far as creating and activating the simple model however I am now trying to invoke the Python shell using 

python manage.py shell

but I keep getting the below error each time. 

C:\Users\Owner\Desktop\Programming\Djang\mysite>python manage.py shell
Traceback (most recent call last):
  File "manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "C:\python27\lib\site-packages\django\core\management\__init__.py", line
399, in execute_from_command_line
    utility.execute()
  File "C:\python27\lib\site-packages\django\core\management\__init__.py", line
392, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "C:\python27\lib\site-packages\django\core\management\base.py", line 242,
 in run_from_argv
    self.execute(*args, **options.__dict__)
  File "C:\python27\lib\site-packages\django\core\management\base.py", line 285,
 in execute
    output = self.handle(*args, **options)
  File "C:\python27\lib\site-packages\django\core\management\base.py", line 415,
 in handle
    return self.handle_noargs(**options)
  File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 81, in handle_noargs
    self.run_shell(shell=interface)
  File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 61, in run_shell
    return getattr(self, shell)()
  File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 44, in ipython
    ip()
  File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 37, in _ipython
    from IPython import start_ipython
  File "C:\python27\lib\site-packages\IPython\__init__.py", line 43, in <module>

    from .config.loader import Config
  File "C:\python27\lib\site-packages\IPython\config\__init__.py", line 16, in <
module>
    from .application import *
  File "C:\python27\lib\site-packages\IPython\config\application.py", line 29, i
n <module>
    from IPython.external.decorator import decorator
  File "C:\python27\lib\site-packages\IPython\external\decorator\__init__.py", l
ine 4, in <module>
    from ._decorator import *
  File "C:\python27\lib\site-packages\IPython\external\decorator\_decorator.py",
 line 165
    print('Error in generated code:', file=sys.stderr)
                                          ^
SyntaxError: invalid syntax

Thanks in advance for any help on this as although I have some experience in Python I'm finding it very hard to follow the Traceback above.

Upvotes: 0

Views: 231

Answers (1)

Maxime Lorant
Maxime Lorant

Reputation: 36141

You are using a Python 3 library (and not backward compatible) with the Python 2.7 version. You need either to reinstall ipython for Python 2 (in C:\python27) or upgrade to Python 3 (and install ipython in C:\python3)

Django is officially compatible with Python 3 since the 1.6 version.

Upvotes: 1

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