CODEWITHSUNDEEP
javascriptjasminespy
Rusty Rob
Rusty Rob

Reputation: 17173

jasmine spy not called

I'm new to jasmine spies.

Here is my test:

spyOn(gapi, 'ready').andCallThrough();
inject(function(_endpointService_) {
  endpointService = _endpointService_;
});        
var _doSteps = gapi.ready.mostRecentCall.args[0];
var wrapper = {_doSteps: _doSteps};
spyOn(wrapper, '_doSteps');
gapi.ready(); //calls _doSteps through promise in service.
//_doSteps();
expect(wrapper._doSteps).wasCalled(); //gives error - not called.

as in my endpointService I have:

gapi.ready($endpointService._doSteps);
return $endpointService;

and my _doSteps method:

_doSteps: function(){
   console.log('in dosteps!');
 },

it logs 'in dosteps!' before the spy complains that _doSteps wasn't called. How do I do this?

Upvotes: 1

Views: 511

Answers (1)

blorkfish
blorkfish

Reputation: 22824

Your spyOn() function returns a spy object - so I'me not sure why you are using mostRecentCall and the wrapper ?

var gapi = new Gapi(); // must create a variable to spy on.
var readySpy = spyOn(gapi, 'ready').andCallThrough();
// .. something that calls gapi.ready here
expect(readySpy).toHaveBeenCalled();

Upvotes: 1

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