CODEWITHSUNDEEP
bashshell
Gabi Radu
Gabi Radu

Reputation: 1107

Populate an bash array with available android devices

I am trying to populate a global variable of type array in a bash shell script. I was using subshell in a function and i understand now that after the code executes all is lost and the global declared var wasn't set with the new value. Now i am trying a different approach but still doesn't seem to work well. This is the code:

declare -a arr
let i=1
function availableDevices {
    while read line #get list of devices
      do
        if [ -n "$line" ] && [ "`echo $line | awk '{print $2}'`" == "device" ]
        then
          device="`echo $line | awk '{print $1}'`"
          echo "Add $device"
          arr[i]="$device"
          let i=$i+1
        fi
      done < <(adb devices)
    echo "devices: ${arr[*]}"
}

When i call this function this error appears:

name.sh: cannot make pipe for process substitution: Function not implemented

I am new to scripting and probably is self explanatory but i don't get it. HOw can the function not be implemented? Thanks

Upvotes: 1

Views: 213

Answers (1)

Deleted User
Deleted User

Reputation: 2541

make sure that there's actually bash, not sh, specified as hash-bang, as it seems that the message comes from using the "< <(" bashism. Also try: line="a b c"; set -- $line; echo 2 see whether that could have any use in your script, instead of echo $line | awk ..., alternatively, "Here strings" are often preferred over piping output of echo. A Here string looks like this (example): rev <<< test

Upvotes: 1

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