user3692128
user3692128

Reputation: 1

array returning error in java

This is my code

import java.util.*;


    public class nebucha {

    public static void main(String[] args) {

        String amac = "amamamafdfdfdfmasssmamasaaaasssamamsamsamsasssss";
        int[] data = budüzen(amac);

        System.out.println("Votes: " + Arrays.toString(data));

    }

    public static int[] budüzen(String amac) {

        int[] saysaysay = new int[3];
        for (int i = 0; i < amac.length(); i++) {
            if (amac.charAt(i) == 'a') {
                saysaysay[0]++;
            } else if (amac.charAt(i) == 'm') {
                saysaysay[1]++;
            } else if (amac.charAt(i) == 's') {
                saysaysay[2]++;
            }
        }
    }

    return saysaysay[] ;
}

i tried to compile it but i dont know why.there was a problem.im seeking a solution

Please help me.

Upvotes: 0

Views: 50

Answers (1)

that other guy
that other guy

Reputation: 123460

Instead of

return saysaysay[];

use

return saysaysay;

and put it inside the budüzen method (it's currently outside).

Here's your class, compilable, will proper indenting. The purpose of indenting is to easily see whether your statements are inside the correct {} block:

import java.util.Arrays;

public class nebucha{
    public static void main(String[]args){
        String amac="amamamafdfdfdfmasssmamasaaaasssamamsamsamsasssss";
        int []data=budüzen(amac);

        System.out.println("Votes: "+Arrays.toString(data));
    }

    public static int [] budüzen(String amac){
        int[] saysaysay = new int[3];
        for(int i=0;i<amac.length();i++){
            if(amac.charAt(i)=='a'){
                saysaysay[0]++;
            }else if(amac.charAt(i)=='m'){
                saysaysay[1]++;
            }else if(amac.charAt(i)=='s'){
                saysaysay[2]++;
            }
        }
        return saysaysay;
    }
}

Upvotes: 4

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