CODEWITHSUNDEEP
vbaexcelhyperlink
user3682866
user3682866

Reputation: 109

Excel VBA Get hyperlink address of specific cell

How do I code Excel VBA to retrieve the url/address of a hyperlink in a specific cell?

I am working on sheet2 of my workbook and it contains about 300 rows. Each rows have a unique hyperlink at column "AD". What I'm trying to go for is to loop on each blank cells in column "J" and change it's value from blank to the hyperlink URL of it's column "AD" cell. I am currently using this code:

do while....
    NextToFill = Sheet2.Range("J1").End(xlDown).Offset(1).Address
    On Error Resume Next
    GetAddress = Sheet2.Range("AD" & Sheet2.Range(NextToFill).Row).Hyperlinks(1).Address
    On Error GoTo 0
loop

Problem with the above code is it always get the address of the first hyperlink because the code is .Hyperlinks(1).Address. Is there anyway to get the hyperlink address by range address like maybe sheet1.range("AD32").Hyperlinks.Address?

Upvotes: 6

Views: 103370

Answers (5)

FreeSoftwareServers
FreeSoftwareServers

Reputation: 2791

This IMO should be a function to return a string like so.

Public Sub TestHyperLink()
 Dim CellRng As Range
 Set CellRng = Range("B3")
 
 Dim HyperLinkURLStr As String
 HyperLinkURLStr = HyperLinkURLFromCell(CellRng)
 Debug.Print HyperLinkURLStr
End Sub

Public Function HyperLinkURLFromCell(CellRng As Range) As String
 HyperLinkURLFromCell = CStr(CellRng.Hyperlinks(1).Address)
End Function

Upvotes: 5

JoeG
JoeG

Reputation: 192

Not sure why we make a big deal, the code is very simple

Sub ExtractURL()
    Dim GetURL As String
    For i = 3 To 500
        If IsEmpty(Cells(i, 1)) = False Then
            Sheets("Sheet2").Range("D" & i).Value = 
               Sheets("Sheet2").Range("A" & i).Hyperlinks(1).Address
        End If
    Next i
End Sub

Upvotes: 5

Jason K.
Jason K.

Reputation: 417

This should work:

Dim r As Long, h As Hyperlink
For r = 1 To Range("AD1").End(xlDown).Row
    For Each h In ActiveSheet.Hyperlinks
        If Cells(r, "AD").Address = h.Range.Address Then
            Cells(r, "J") = h.Address
        End If
    Next h
Next r

It's a bit confusing because Range.Address is totally different than Hyperlink.Address (which is your URL), declaring your types will help a lot. This is another case where putting "Option Explicit" at the top of modules would help.

Upvotes: 3

abhinov
abhinov

Reputation: 154

Try to run for each loop as below:

do while....
    NextToFill = Sheet2.Range("J1").End(xlDown).Offset(1).Address
    On Error Resume Next
    **for each** lnk in Sheet2.Range("AD" & Sheet2.Range(NextToFill).Row).Hyperlinks
         GetAddress=lnk.Address
    next
On Error GoTo 0
loop

Upvotes: 0

D Mason
D Mason

Reputation: 86

My understanding from the comments is that you already have set the column J to a string of the URL. If so this simple script should do the job (It will hyperlink the cell to the address specified inside the cell, You can change the cell text if you wish by changing the textToDisplay option). If i misunderstood this and the string is in column AD simply work out the column number for AD and replace the following line:

fileLink = Cells(i, the number of column AD)

The script:

Sub AddHyperlink()

Dim fileLink As String

Application.ScreenUpdating = False

With ActiveSheet
lastrow = .Cells(.Rows.Count, "A").End(xlUp).Row


For i = 4 To lastrow

    fileLink = Cells(i, 10)

    .Hyperlinks.Add Anchor:=Cells(i, 10), _
    Address:=fileLink, _
    TextToDisplay:=fileLink

Next i

End With

Application.ScreenUpdating = True

End Sub

Upvotes: 0

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