CODEWITHSUNDEEP
phpclassoop
Alex Coroza
Alex Coroza

Reputation: 1757

Method from another class called from inside a class

I dont know if its possible in PHP. I tried this code but I got error.

class UserAccount extends classDatabase
{
    $validate = new classValidate;
    function login($user, $pass)
    {
       //access a method from classValidate
       $validate->checkInput($user);
    }
}

I want to validate user input by using a method from classValidate. How to do that? I can't extend classValidate because I already extend classDatabase.

Please tell me a way how to do this.

Upvotes: 0

Views: 60

Answers (2)

scragar
scragar

Reputation: 6824

class UserAccount extends classDatabase
{
    $validate = null;

    function __construct(){
        $this->validate = new classValidate;
    }

    function login($user, $pass)
    {
       //access a method from classValidate
       $this->validate->checkInput($user);
    }
}

Or with scope for added to make it not throw warnings on PHP5

class UserAccount extends classDatabase
{
    private $validate = NULL;

    function __construct(){
        $this->validate = new classValidate();
    }

    public function login($user, $pass)
    {
       //access a method from classValidate
       $this->validate->checkInput($user);
    }
}

Upvotes: 0

complex857
complex857

Reputation: 20753

Your example code has a syntax error:

class UserAccount extends classDatabase
{
     $validate = new classValidate; // <-- in php you can't do this

First you need to specify an access modifier like public, protected, private or at least var. Second, php can't "run" code in the declaration, the = new ClassValidate will not work here, only constants or literals like 42 or "some string" or results of a static method call (see docs)

You can move the instantiation to the constructor like this:

public function __construct() {
    $this->validate = new ClassValidate;
}

Note the explicit $this->, in php you will always have to type this out.

Finally you need to use the instance in login() properly:

function login($user, $pass) {
    $this->validate->checkInput($user);
}

Upvotes: 1

Related Questions