Reputation: 529
I have a base directory, call it MAIN and two subfolders, SCRIPTS and WORK. When using the following line of code, the script calls upon the job and runs it, only if job_name is in the MAIN folder, then prints output or error to job_name.out/.err in the WORK folder.
system("$job_name > ./WORK/$job_name.out 2> ./WORK/$job_name.err");
If I move the jobs into SCRIPTS then I cannot seem to find an efficient/simple way to call upon it.. I figured something similar to the following code would work:
system("SCRIPTS/$job_name > ./WORK/$job_name.out 2> ./WORK/$job_name.err");
But I get errors like:
SCRIPTS is not recognized as an internal or external command......
The system cannot find the path specified.
How can I compose this command to get it to work from a subdirectory?
Upvotes: 1
Views: 594
Reputation: 37146
On Windows, filepaths are specified with backslashes (\
).
Instead of system("SCRIPTS/$job_name"...)
, try system("SCRIPTS\\$job_name"...)
Upvotes: 3