CODEWITHSUNDEEP
regexgroovy
Cthulhujr
Cthulhujr

Reputation: 433

Using backslashes in Groovy

I'm using groovy to write a script that replaces UNC server names and a part of the directory structure. I have the following:

def patternToFind = /\\\\([a-zA-Z0-9-]+)\\share\\([a-zA-Z]+)/
def patternToReplace = '\\\\\\\\SHARESERVER\\\\share\\\\OPS'

This works, but all those \'s are pretty ugly. I understand in the regex why \\\\ is used to find \\, but what is confusing me is why in the replacement I'm doing I have to use four \'s to equal one \.

If anyone has a nicer way to do this I would greatly appreciate it. The goal is to replace

\\<server>\share\<env>

with the correct value for <server> and <env>

Thanks!

EDIT: I guess I should clarify. SHARESERVER and OPS are actually variables. So truly the end result would be something like:

def serverName = //some passed in server
def env = //some passed in env

def patternToFind = /\\\\([a-zA-Z0-9-]+)\\NAS\\([a-zA-Z]+)/
def patternToReplace = '\\\\\\\\' + serverName + '\\\\share\\\\' + env

So the only way I think of doing it is building a string literal to replace the section I'm looking for with.

And I'll be the first to admit that I suck at reg ex, so if you can use them to capture a value in a string and replace just that value with another, I'm all ears.

Upvotes: 2

Views: 3249

Answers (2)

Ian Roberts
Ian Roberts

Reputation: 122414

If you want to use a literal replacement string (as opposed to one that involves $n backreferences) with a regular expression in Java then the safest thing to do is use Matcher.quoteReplacement:

def patternToReplace = Matcher.quoteReplacement(/\\SHARESERVER\shares\OPS/)

Upvotes: 1

tim_yates
tim_yates

Reputation: 171194

Doesn't it work with

def patternToReplace = $/\\SHARESERVER\share\OPS/$

Upvotes: 2

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