CODEWITHSUNDEEP
c#asp.net-mvcrazor
Noah Crowley
Noah Crowley

Reputation: 455

Render Dynamic String as Razor

I'm trying to render a string that is stored in my database as if it were from a CSHTML file. Here is a sample string that I'd like to render:

<footer>
    <div class="content-wrapper">
        <div class="float-left">
            <p>&copy; @DateTime.Now.Year - My ASP.NET MVC Application</p>
        </div>
    </div>
</footer>

Notice that "@DateTime.Now.Year"? Well, if this were stored in a database, how would I render this into a view and have that part of it actually render as 2014 (or whatever year it is that you're reading this)?

Upvotes: 1

Views: 2819

Answers (3)

Peter
Peter

Reputation: 3956

You can use RazorEngine (NuGet package "RazorEngine") for this.

Package Manager Console:

PM> install-package razorengine

In your code:

string template = GetYourTemplateFromDatabase();
string content = RazorEngine.Razor.Parse(template, null);

If you want to add this output to your actual view you would have to add it as an IHtmlString or use @Html.Raw(ViewBag.Content):

Controller code (for IHtmlString):

ViewBag.DatabaseCode = MvcHtmlString.Create(content);

View code:

<div>
    @ViewBag.DatabaseCode
</div>

Upvotes: 5

dom
dom

Reputation: 6832

If I understand correctly, you're storing that whole HTML snippet in the database? You could do a simple String.Replace on the string you get from the database.

<footer>
    <div class="content-wrapper">
        <div class="float-left">
            <p>&copy; {{YEAR}} - My ASP.NET MVC Application</p>
        </div>
    </div>
</footer>

And then in the view :

@Html.Raw(Model.Footer.Replace("{{YEAR}}", DateTime.Now.Year))

Upvotes: 0

Ignacio Laborde
Ignacio Laborde

Reputation: 1462

you need define a model in razor this is a good example http://weblogs.asp.net/scottgu/asp-net-mvc-3-new-model-directive-support-in-razor

Upvotes: 0

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