CODEWITHSUNDEEP
swift
PissyB
PissyB

Reputation: 23

Could not find an overload for '-' that accepts the supplied arguments

I am just playing around with Swift for the first time and I do not understand why this does not work. Any help would be great!

I get the error could not find an overload for '-' that accepts the supplied arguments

for the line that says self.health = self.health - amount

class human {
    var name:String
    var height:Integer
    var hairColor:String
    var health:Integer

    init(name:String, height:Integer, hairColor:String) {
        self.name = name
        self.height = height
        self.hairColor = hairColor
        self.health = 100
    }

    func applyDamage(amount:Integer) -> Integer{
        self.health = self.health - amount
        return self.health
    }
}

Thank you!

Upvotes: 2

Views: 3216

Answers (4)

Bob Sutor
Bob Sutor

Reputation: 71

For what it is worth, you might want to do

self.health -= amount

instead of

self.health = self.health - amount

to be more idiomatic

Upvotes: 2

Tash Pemhiwa
Tash Pemhiwa

Reputation: 7695

To explain the actual error message, Swift is trying to apply the '-' operator to an Integer and an Integer, but you have not overloaded the '-' operator. This is why the error is worded as it is. The '-' operators works in the case of an Int and an Int, which was obviously your intention in this instance, so you simply need to use Int instead of Integer

Upvotes: 3

Connor
Connor

Reputation: 64694

I think you may have meant to use Int instead of Integer. This code works fine:

class human {
    var name:String
    var height:Int
    var hairColor:String
    var health:Int

    init(name:String, height:Int, hairColor:String) {
        self.name = name
        self.height = height
        self.hairColor = hairColor
        self.health = 100
    }

    func applyDamage(amount:Int) -> Int{
        self.health = self.health - amount
        return self.health
    }
}

Upvotes: 0

Cezary Wojcik
Cezary Wojcik

Reputation: 21845

Use Int, not Integer.

Integer is a protocol, not the type.

Upvotes: 9

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