Reputation: 79299
How can I test if a string contains only whitespace?
Example strings:
" "
(space, space, space)
" \t \n "
(space, tab, space, newline, space)
"\n\n\n\t\n"
(newline, newline, newline, tab, newline)
Upvotes: 314
Views: 327628
Reputation: 82924
str.isspace() returns False
for a valid and empty string
>>> tests = ['foo', ' ', '\r\n\t', '']
>>> print([s.isspace() for s in tests])
[False, True, True, False]
Therefore, checking with not
will also evaluate None
Type and ''
or ""
(empty string)
>>> tests = ['foo', ' ', '\r\n\t', '', None, ""]
>>> print ([not s or s.isspace() for s in tests])
[False, True, True, True, True, True]
Upvotes: 81
Reputation: 4966
Use the str.isspace()
method:
Return
True
if there are only whitespace characters in the string and there is at least one character,False
otherwise.A character is whitespace if in the Unicode character database (see unicodedata), either its general category is Zs (“Separator, space”), or its bidirectional class is one of WS, B, or S.
Combine that with a special case for handling the empty string.
Alternatively, you could use str.strip()
and check if the result is empty.
Upvotes: 431
Reputation: 3488
Resemblence with c# string static method isNullOrWhiteSpace.
def isNullOrWhiteSpace(str):
"""Indicates whether the specified string is null or empty string.
Returns: True if the str parameter is null, an empty string ("") or contains
whitespace. Returns false otherwise."""
if (str is None) or (str == "") or (str.isspace()):
return True
return False
isNullOrWhiteSpace(None) -> True // None equals null in c#, java, php
isNullOrWhiteSpace("") -> True
isNullOrWhiteSpace(" ") -> True
Upvotes: 5
Reputation: 464
To check if a string is just a spaces or newline
Use this simple code
mystr = " \n \r \t "
if not mystr.strip(): # The String Is Only Spaces!
print("\n[!] Invalid String !!!")
exit(1)
mystr = mystr.strip()
print("\n[*] Your String Is: "+mystr)
Upvotes: 1
Reputation: 6077
I used following:
if str and not str.isspace():
print('not null and not empty nor whitespace')
else:
print('null or empty or whitespace')
Upvotes: 2
Reputation: 675
Check the length of the list given by of split() method.
if len(your_string.split()==0:
print("yes")
Or Compare output of strip() method with null.
if your_string.strip() == '':
print("yes")
Upvotes: 6
Reputation: 3819
Here is an answer that should work in all cases:
def is_empty(s):
"Check whether a string is empty"
return not s or not s.strip()
If the variable is None, it will stop at not s
and not evaluate further (since not None == True
). Apparently, the strip()
method takes care of the usual cases of tab, newline, etc.
Upvotes: 3
Reputation: 17498
I'm assuming in your scenario, an empty string is a string that is truly empty or one that contains all white space.
if(str.strip()):
print("string is not empty")
else:
print("string is empty")
Note this does not check for None
Upvotes: 2
Reputation: 24866
You want to use the isspace()
method
str.isspace()
Return true if there are only whitespace characters in the string and there is at least one character, false otherwise.
That's defined on every string object. Here it is an usage example for your specific use case:
if aStr and (not aStr.isspace()):
print aStr
Upvotes: 40
Reputation: 4212
for those who expect a behaviour like the apache StringUtils.isBlank or Guava Strings.isNullOrEmpty :
if mystring and mystring.strip():
print "not blank string"
else:
print "blank string"
Upvotes: 15