Reputation: 11741
I have an Option[String]
.
I want to check if there is a string exists and if it's exists its not blank.
def isBlank( input : Option[String]) : Boolean =
{
input.isEmpty ||
input.filter(_.trim.length > 0).isEmpty
}
Is there is a better way of doing this in Scala ?
Upvotes: 37
Views: 95691
Reputation: 19733
you can also check using lastOption
or headOption
if the string is empty it will return None
scala> "hello".lastOption
res39: Option[Char] = Some(o)
scala> "".lastOption
res40: Option[Char] = None
Upvotes: -1
Reputation: 10751
You can also take advantage of Extractor pattern. It makes codes much more declarative.
For example:
object NonBlank {
def unapply(s: String): Option[String] = Option(s).filter(_.trim.nonEmpty)
}
And then use it like
def createUser(name: String): Either[Error, User] = name match {
case NonBlank(username) => Right(userService.create(username))
case _ => Left(new Error("Invalid username. Blank usernames are not allowed."))
}
Upvotes: 1
Reputation: 14803
I added a Scalafiddle to play with that: Scalafiddle
That shows the marked correct answer is wrong (as pointed out by prayagupd):
def isBlank(str: Option[String]): Boolean =
str.forall(_.trim.isEmpty)
the solution is for non-blank:
def isNotBlank(str: Option[String]): Boolean =
str.exists(_.trim.nonEmpty)
Upvotes: 1
Reputation: 31192
exists
(Accepted solution) will work when input has at least one element in it, that is Some("")
but not when it's None
.
exists
checks if at least one element(x
) applies to function.
eg.
scala> List[String]("apple", "").exists(_.isEmpty)
res21: Boolean = true
//if theres no element then obviously returns false
scala> List[String]().exists(_.isEmpty)
res30: Boolean = false
Same happens with Option.empty
, as theres no element in it,
scala> Option.empty[String].exists(_.isEmpty)
res33: Boolean = false
So forall
is what makes sure the the function applies all the elements.
scala> def isEmpty(sOpt: Option[String]) = sOpt.forall(_.trim.isEmpty)
isEmpty: (sOpt: Option[String])Boolean
scala> isEmpty(Some(""))
res10: Boolean = true
scala> isEmpty(Some("non-empty"))
res11: Boolean = false
scala> isEmpty(Option(null))
res12: Boolean = true
The gross way is to filter nonEmpty
string, then check option.isEmpty
.
scala> def isEmpty(sOpt: Option[String]) = sOpt.filter(_.trim.nonEmpty).isEmpty
isEmpty: (sOpt: Option[String])Boolean
scala> isEmpty(None)
res20: Boolean = true
scala> isEmpty(Some(""))
res21: Boolean = true
Upvotes: 5
Reputation: 35895
I am from C# background and found Scala implicit methods similar to C# extensions
import com.foo.bar.utils.MyExtensions._
...
"my string".isNullOrEmpty // false
"".isNullOrEmpty // true
" ".isNullOrEmpty // true
" ".isNullOrEmpty // true
val str: String = null
str.isNullOrEmpty // true
Implementation
package com.foo.bar.utils
object MyExtensions {
class StringEx(val input: String) extends AnyVal {
def isNullOrEmpty: Boolean =
if (input == null || input.trim.isEmpty)
true
else
false
}
implicit def isNullOrEmpty(input: String): StringEx = new StringEx(input)
}
Upvotes: 1
Reputation: 21
All proposed solutions will crash with NullPointerException if you pass:
val str : Option[String] = Some(null).
Therefore null-check is a must:
def isBlank(input: Option[String]): Boolean =
input.filterNot(s => s == null || s.trim.isEmpty).isEmpty
Upvotes: 2
Reputation: 20405
An approach based in pattern matching,
def isBlank( input : Option[String]) : Boolean =
input match {
case None => true
case Some(s) => s.trim.isEmpty
}
Upvotes: 6
Reputation: 81862
This should work as well since filter of an empty Option results in an empty Option
def isBlank( input : Option[String]) : Boolean =
input.filter(_.trim.length > 0).isEmpty
Upvotes: 3
Reputation: 35970
What you should do is check using exists
. Like so:
myOption.exists(_.trim.nonEmpty)
which will return True
if and only if the Option[String]
is not None
and not empty.
Upvotes: 76