CODEWITHSUNDEEP
bashshell
user1993893
user1993893

Reputation: 99

How to renumber files using script?

How would I renumber files in a directory like "ab0001.xyz" "ab0002.xyz" ... "ab0200.xyz" to the same numbering but adding a constant (say 97), so "ab0098.xyz" "ab0099.xyz"... "ab0297.xyz"

Also if you could add just a bit of commentary on each function so I don't have to ask again for something similar.

Thanks!

Upvotes: 0

Views: 215

Answers (2)

Diego Sevilla
Diego Sevilla

Reputation: 29021

The solution depends on several things. For example, if you have always the same names and always are going to have four digit numbers, the solution is somewhat easier. For example:

CONSTANT=97
for i in `echo ab*.xyz | sort -r` ; do
   filenumber=`echo $i | tr -dc 0-9`
   numberadd=`expr $filenumber + $CONSTANT`
   mv $i ab`printf "%04d" $numberadd`.xyz
done

You've got the CONSTANT defined, then you extract just the numbers in the name and use them to sum it with the constant with expr. Then, you change the name of the file using printf to print just 4 digits filled with zeros.

Upvotes: 1

plesiv
plesiv

Reputation: 7028

You could use this script. Execute in the same directory where files are located. I'm sure there are more concise solutions...

#/usr/bin/env bash
export BASN=ab     # basename
export EXT=xyz     # extension
export CONST=97    # constant to add

for fl in ${BASN}*.${EXT}; do
    noe=${fl%%.${EXT}}   # trim extension
    num=${noe##${BASN}}  # trim basename
    tar=${BASN}`printf '%04d' $((num + ${CONST}))`.${EXT}  # construct target
    mv ${fl} ${tar}
done

Upvotes: 1

Related Questions