CODEWITHSUNDEEP
androidjsonarrays
M.Movaffagh
M.Movaffagh

Reputation: 1312

Parse JsonArray without key in android

i have a json response but is this standard format?

[{"code":"123","rate":"0.1","title":"sss","subtitle":"mmm"},{"code":"456","rate":"0.1","title":"bbb","subtitle":"uuu"}]

and how can i pars it in android?

new JSONObject(result.toString())

throw below exception!

06-07 11:45:54.943: W/System.err(10310):    at org.json.JSON.typeMismatch(JSON.java:111)
06-07 11:45:54.943: W/System.err(10310):    at org.json.JSONObject.<init>(JSONObject.java:158)
06-07 11:45:54.943: W/System.err(10310):    at org.json.JSONObject.<init>(JSONObject.java:171)

Upvotes: 1

Views: 4555

Answers (3)

VairavelRajendran
VairavelRajendran

Reputation: 56

First assign your json array like this

JSONArray jsar=new JSONArray(result);

then parse objects like this

for(int i=0;i<jsar.length;i++)
{
JSONObject jsobj=new JSONObject(jsar[i]);

String strcode=jsobj.get("code");

String strrate=jsobj.get("rate");

String strtitle=jsobj.get("title");

String strsubtitle=jsobj.get("subtitle");
}

hope this will help you,.

Upvotes: 1

MilapTank
MilapTank

Reputation: 10076

this is JSONarray 

[{"code":"123","rate":"0.1","title":"sss","subtitle":"mmm"},{"code":"456","rate":"0.1","title":"bbb","subtitle":"uuu"}]

try to parse 

 new JSONArray(result.toString())

Upvotes: 3

T.J. Crowder
T.J. Crowder

Reputation: 1074595

i have a json response but is this standard format?

It would be without the < at the beginning and the > at the end. So:

new JSONObject(result.toString().substring(1, result.length() - 2));

or more likely:

new JSONArray(result.toString().substring(1, result.length() - 2));

since the top level of it is an array.

Since you've removed the < and > you had originally:

Since the top level of it is an array, you probably want JSONArray, not JSONObject:

new JSONArray(result.toString());

Upvotes: 3

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