CODEWITHSUNDEEP
bash
user3699907
user3699907

Reputation: 23

Bash script - Printing every char in a new line

My script should get a string and print every char(including space,!@#$ etc.) in a new line

The script works on standart input but fails when some of the special chars appears in the string

here's my script

#!/bin/bash
if (($#!=1)); then
    echo Please enter one string
    exit 0 
fi

 string="$1"
 num=`expr length $string`

 for (( i=1; i<=num; i++ )); do
 x=`expr substr $string $i 1`
 echo  "$x"
 done

exit 0

Whats wrong?

Upvotes: 1

Views: 967

Answers (2)

Barmar
Barmar

Reputation: 780673

Always quote your variables unless you WANT word splitting and wildcard expansion:

num=$(expr length "$string")

x=$(expr substr "$string" "$i" 1)

Upvotes: 1

anubhava
anubhava

Reputation: 784888

To print each character in BASH you can do this without calling any external utility:

for ((i=0; i<${#string}; i++)); do
   echo "${string:i:1}"
done

Upvotes: 3

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