CODEWITHSUNDEEP
java
Altaïr
Altaïr

Reputation: 123

Unreachable code in Java

I don't get what does "unreachable code" means ?

Here in the last line of my code double probabilityOfWin = wins / (wins + loses); it says unreachable code.

import java.util.Random;

 public class CrapsGame {
    public static final int GAMES = 9999;

public static void main(String[] args) {
    Random randomGenerator1 = new Random();
    Random randomGenerator2 = new Random();
    Random randomGenerator3 = new Random();
    Random randomGenerator4 = new Random();

    int dice1 = randomGenerator1.nextInt(6) + 1;
    int dice2 = randomGenerator2.nextInt(6) + 1;

    int comeoutSum = dice1 + dice2;
    int point = 0;

    // The comeout roll

    if (comeoutSum == 7 || comeoutSum == 12)
        System.out.println("wins");
    else if ( comeoutSum == 2 || comeoutSum == 3 || comeoutSum == 12)
        System.out.println("loses");
    else
         point = comeoutSum;

    int wins = 0;
    int loses = 0;


    while(GAMES <= 9999)
    {
        dice1 = randomGenerator3.nextInt(6) + 1;
        dice2 = randomGenerator4.nextInt(6) + 1;
        int sum = dice1 + dice2;

        if (sum == point)
            wins++;
        else if (sum == 7)
            loses++;
    }

    double probabilityOfWin = wins / (wins + loses);


}

}

Upvotes: 0

Views: 205

Answers (2)

AntonH
AntonH

Reputation: 6437

This loop here:

while(GAMES <= 9999)
{
    ...
}

resolves to while (true) because the value of GAMES is never modified. So any code that comes after (in your case, double probabilityOfWin = wins / (wins + loses);) is deemed unreachable.

Upvotes: 2

zyl1024
zyl1024

Reputation: 700

You did not make any change to the constant GAME. So while loop will never terminate. Last line of code is unreachable. Unreachable means the code never gets executed. For example, 

return 15;
int a = 12;

Then the last line of code will not get executed because the function has already returned.

Upvotes: 0

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