CODEWITHSUNDEEP
rsurvival-analysisweibullmixture-model
rose
rose

Reputation: 1981

Simulation from mixture distribution in R

I would like to simulate data set which has a decreasing and then increasing hazard from 3 weibull distributions but I would like to have this hazard function more near to zerohow can I get around 0.1 or less. How can I fix my code to have this?

Upvotes: 1

Views: 771

Answers (1)

IRTFM
IRTFM

Reputation: 263301

It's not necessary to use pexp and rexp, because the Exponential is a degenerate case of the Weibull distribution when the shape parameter=1. Shapes less than 1 are going to be even more "scoopy" near the origin. You could get a nice bathtubwith just two Weibull, but since you had one with three, I just made some minor alterations:

 hazmix = function(w1, w2, x) {w1*dweibull(x,.8, 1)/(1-pweibull(x, .8, 1))+ 
    + w2*dweibull(x,1,.5) + 
    ((1-(w1+w2))* dweibull(x, 6, 10)/(1-pweibull(x, 6, 10)))}

 png();plot(hazmix(.2,.4, seq(0, 10, by=.1)), ylim=c(0,1) ); dev.off()

enter image description here

I don't promise that it's normalized and if you needed a normalized distribution it would be much easier to just use two Weibulls with one mixing parameter.

Upvotes: 2

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