CODEWITHSUNDEEP
javascriptregex
David542
David542

Reputation: 110143

Replace a querystring in url in javascript

I have the following two urls:

url1 = http://localhost:8000/i/dashboard-view?
&level_to_load=1&click_value=%C2%AB%20backll%20Billing%20PartiesC2%
AB%20backll%20Billing%20Parties 

url2 = http://localhost:8000/i/dashboard-view?&level_to_load=1
&click_value=%C2%AB%20backll%20Billing%20PartiesC2%AB%20backll%20Billing%20Parties
&new_value=2

I want to be able to pull out the part that contains "click_value=...".

The resulting two urls after the regular expression should then be:

url1 = http://localhost:8000/i/dashboard-view?&level_to_load=1

url2 = http://localhost:8000/i/dashboard-view?&level_to_load=1&new_value=2

The current regex I have is:

url.replace(/click_value=.+&/, '');

But it is obviously insufficient. What would be the correct regex here?

Upvotes: 1

Views: 70

Answers (1)

zx81
zx81

Reputation: 41838

You can match the click_value GET strings with this regex:

&?click_value=[^&#\s]*

Therefore, to nix them,

result = url.replace(/&?click_value=[^&#\s]*/mg, "");

Discussion

The key here is matching the right number of characters and no more. I revised my original answer after @ridgerunner's insightful observation that in many urls, though maybe not in yours, there can be an anchor tag at the end, starting with #, which we don't want to replace. Thanks to him for the improved answer, which no longer uses lookaheads.

Token-by-Token

&?                       # '&' (optional (matching the most amount
                         # possible))
click_value=             # 'click_value='
[^&#\s]*                 # any character except: '&', '#', whitespace
                         # (\n, \r, \t, \f, and " ") (0 or more times
                         # (matching the most amount possible))

Upvotes: 2

Related Questions