CODEWITHSUNDEEP
phpregexquotes
Aaron Turecki
Aaron Turecki

Reputation: 355

php - get content from second pair of quotes in string

I'm trying to get the contents of the second quotes and only the second quotes from a string. Right now I'm able to get the contents of all three quotes. What am I doing wrong? Is it possible to just print the second value in the output array?

Text

2014-06-02 11:48:41.519 -0700   Information 94  NICOLE  Client "[WebDirect] (207.230.229.204) [207.230.229.204]" opening database "FMServer_Sample" as "Admin".

PHP 

if (preg_match_all('~(["\'])([^"\']+)\1~', $line, $matches))
                $database_names = $matches[2];

print_r($database);

Output

[WebDirect] (207.230.229.204) [207.230.229.204], FMServer_Sample, Admin

Upvotes: 2

Views: 339

Answers (2)

anubhava
anubhava

Reputation: 786289

You can use it this way:

$re = '~(["\'])[^"\']+\1[^"\']*(["\'])([^"\']+)\1~';
$str = '2014-06-02 11:48:41.519 -0700   Information 94  NICOLE  Client "[WebDirect] (207.230.229.204) [207.230.229.204]" opening database "FMServer_Sample" as "Admin".';

if ( preg_match($re, $str, $m) )
   echo $m[3]; // FMServer_Sample

Upvotes: 3

l'L'l
l'L'l

Reputation: 47292

The match group starts at [0] and since you're using preg_match_all you get [3] groups. The array is the first array of $matches, so it also starts at zero. You could use it like this:

if (preg_match_all('~(["\'])([^"\']+)\1~', $line, $matches))
                $database_names = $matches[0][1];

print_r($database_names);

Upvotes: 0

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