CODEWITHSUNDEEP
pythonformattingdecimalpercentage
Tahmoor Cyan
Tahmoor Cyan

Reputation: 129

Converting Decimal to %

So I have looked at the post here: how to show Percentage in python and used the solution. 

S = 'ftp'
"{0:.0f}%".format(S.count('f') / 9 * 100)

The desired output is 11%, but when I run the code using the format specified I get "0%" instead of the 11% that I want. Any push in the right direction would be much appreciated.

Upvotes: 0

Views: 4554

Answers (4)

poke
poke

Reputation: 388313

If you want to show a percentage, you should just use the percent formatter directly:

>>> '{:.0%}'.format(S.count('f') / 9)
'11%'

As others already noted, Python 2 will use integer division if both arguments are integers, so you can just make the constant a float instead:

>>> '{:.0%}'.format(S.count('f') / 9.)
'11%'

Upvotes: 1

paxdiablo
paxdiablo

Reputation: 882606

It's because (in Python 2) you're using integer division where 3 / 9 gives you zero.

You can switch to floating point division:

"{0:.0f}%".format(S.count('f') / 9.0 * 100)

and you'll see why that works in the following transcript:

>>> 3/9
0

>>> 3/9.0
0.3333333333333333

Alternatively, you can rearrange your operations so that you multiply first:

"{0:.0f}%".format(S.count('f') * 100 / 9)

Upvotes: 0

furas
furas

Reputation: 143097

It works in Python 3 but for Python 2 you need atleast one float number to get float result for /

You can add . (dot) to 9 to have float number.

S = 'ftp'
"{0:.0f}%".format(S.count('f') / 9. * 100)

Upvotes: 0

Ajean
Ajean

Reputation: 5659

The problem is not in the format statement, just the arithmetic - your integer division makes S.count('f') / 9 return 0. Changing your 9 to 9.0 should work.

Upvotes: 1

Related Questions