Reputation: 4719
I have an array of devices (ibm, sony, dell) in different shops (to simplify shops 1,2,3). What I have to do is to create a comparison of shops which have all products. In example below the only shop which match the condition is shop_id: 2 (shop 1 doesn't have dell & shop 3 doesn't sell ibm).
Example:
[
[ {"id": "1", "name": "ibm", "price": "22", "shop_id": "1"}, {"id": "2", "name": "ibm", "price": "27", "shop_id": "1"}, {"id": "3", "name": "ibm", "price": "21", "shop_id":" 2"} ],
[ {"id": "4", "name": "sony", "price": "19", "shop_id": "1"}, {"id": "5", "name": "sony", "price": "21", "shop_id": "2"}, {"id": "6", "name": "sony", "price": "28", "shop_id": "3"} ],
[ {"id": "7", "name": "dell", "price": "22", "shop_id": "2"}, {"id": "8", "name": "dell", "price": "27", "shop_id": "2"}, {"id": "9", "name": "dell", "price": "21", "shop_id": "3"} ]
]
has to be transformed to:
[
[ {"id": "3", "name": "ibm", "price": "21", "shop_id": "2"}, {"id": "5", "name": "sony", "price": "21", "shop_id": "2"}, {"id": "7", "name": "dell", "price": "22", "shop_id": "2"}],
[ {"id": "3", "name": "ibm", "price": "21", "shop_id": "2"}, {"id": "5", "name": "sony", "price": "21", "shop_id": "2"}, {"id": "8", "name": "dell", "price": "27", "shop_id": "2"}]
]
I have to do it in PHP but all I need is an algorithm to solve this. There is an unlimited number of devices - only 3 shops for now but it might be more so assume it's unlimited too.
What I have so far almost work... but it breaks when there is more then one deal for a device in one shop (it gets only the first deal).
public function getDeals($prices){
// define return array
$multi_deals = array();
// get number of devices
$no_devices = count($prices);
// loop over each deal for first device
foreach ($prices[0] as $dd){
// reset other arrays
for ($j=1; $j<$no_devices; $j++)
reset($prices[$j]);
// remember deal shop
$shop = $dd['shop_id'];
$success = true;
$i=0;
// remember deal
$multi_deal = array();
$multi_deal[$i] = $dd;
// loop over rest of the devices
while ($i < ($no_devices-1)){
$i++;
// only continue if found a deal from the same shop
if ( !($multi_deal[$i] = self::getDevice($shop, $prices[$i]))){
$success = false;
break;
}
// THIS IS WHERE PRICES ARRAY WILL BE RESET IF THE SAME DEVICE IS TWICE IN ONE SHOP
}
// we looped over all devices and find deals for each one of them
if ($success)
$multi_deals[] = $multi_deal;
}
}
public function getDevice($current_shop, &$deals){
while ($deal = next($deals)){
if ($deal['shop_id'] == $current_shop)
return $deal;
}
return false;
}
I'm trying to get my head around it for few hours now, so I'll appreciate any clues.
UPDATE:
Imagine you have suppliers (shops) selling the products (ibm, sony, dell). As a customer I want to buy 1*ibm + 1*sony + 1*dell and it has to be from one shop.
As a results I need to show full list of possible deals, split by shops
In the example I gave there is only one shop which has all free products - shop_id: 2. What is more this shop have 2 deals for dell. That's why as a results we have two sets as there are two possible combinations.
UPDATE 2:
I've tried different approach and I think I'm getting closer. I got to a point where I have
[
{ "shop_id": "2", "deals": [
{ "ibm": [
{"id": "3", "name": "ibm", "price": "21", "shop_id":" 2"}
] },
{ "sony": [
{"id": "5", "name": "sony", "price": "21", "shop_id": "2"}
] },
{ "dell": [
{"id": "7", "name": "dell", "price": "22", "shop_id": "2"},
{"id": "8", "name": "dell", "price": "27", "shop_id": "2"}
] }
] }
]
which again has to transformed into:
[
[ {"id": "3", "name": "ibm", "price": "21", "shop_id": "2"}, {"id": "5", "name": "sony", "price": "21", "shop_id": "2"}, {"id": "7", "name": "dell", "price": "22", "shop_id": "2"}],
[ {"id": "3", "name": "ibm", "price": "21", "shop_id": "2"}, {"id": "5", "name": "sony", "price": "21", "shop_id": "2"}, {"id": "8", "name": "dell", "price": "27", "shop_id": "2"}]
]
Upvotes: 0
Views: 116
Reputation: 4157
Whoopie, that was fun figuring out. Especially the part of 'flattening' the offers array :-) I have a solution for you, not in a class, but maybe you could use some elements of it. It is flexible, so you could add as many stores and searchitems as you like.
$search = array('ibm','sony','dell','apple'); //the words to search for
$shop=array();
//Populate shop array with first machine
foreach($prices[0] as $offer){
$shop[$offer['shop_id']][0][]=$offer;
}
//Loop trough rest of machines
$t=1;
foreach($prices as $k=>$machine){
if($k==0)continue; //skip the first one, we've done that
$t++;
foreach($machine as $offer){
//if this shop_id not exists => continue
if(!isset($shop[$offer['shop_id']]))continue;
$shop[$offer['shop_id']][$k][]=$offer; //add offer to shop
}
foreach($shop as $id=>$v){
//if the count of machines not right => dump this shop
if(count($v)!=$t){
unset($shop[$id]);
}
}
}
//echo '<pre>'.print_r($shop,true).'</pre>';
$shop
now contains all the shops that have the combined machines on offer, and per shop an array of machine-offers.
//'Flatten' the shop-array, combining all possibilities
$offers=array();
foreach($shop as $array){
$return=array();
foreach($array as $k=>$machine){
//first machine: populate $return
if($k==0){
foreach($array[0] as $k=>$v){$return[$k][0]=$v;}
continue;
}
$w=$return;
$return=array();
foreach($machine as $offer){
foreach($w as $r){
$r[]=$offer;
$return[]=$r;
}
}
}
$offers=array_merge($offers,$return);
}
//echo '<pre>'.print_r($offers,true).'</pre>';
I used this array to test:
$prices = array(
array(
array("id"=> "2", "name"=> "ibm", "price"=> "27", "shop_id"=> "11"),
array("id"=> "3", "name"=> "ibm", "price"=> "21", "shop_id"=> "22"),
array("id"=> "10", "name"=> "ibm", "price"=> "44", "shop_id"=> "22"),
),
array(
array("id"=> "4", "name"=> "sony", "price"=> "19", "shop_id"=> "11"),
array("id"=> "5", "name"=> "sony", "price"=> "21", "shop_id"=> "22"),
array("id"=> "6", "name"=> "sony", "price"=> "28", "shop_id"=> "33"),
),
array (
array("id"=> "7", "name"=> "dell", "price"=> "22", "shop_id"=> "11"),
array("id"=> "7", "name"=> "dell", "price"=> "44", "shop_id"=> "11"),
array("id"=> "7", "name"=> "dell", "price"=> "22", "shop_id"=> "22"),
array("id"=> "8", "name"=> "dell", "price"=> "27", "shop_id"=> "22"),
array("id"=> "9", "name"=> "dell", "price"=> "21", "shop_id"=> "33")
),
array (
array("id"=> "17", "name"=> "apple", "price"=> "22", "shop_id"=> "11"),
array("id"=> "17", "name"=> "apple", "price"=> "22", "shop_id"=> "22"),
array("id"=> "18", "name"=> "apple", "price"=> "27", "shop_id"=> "22"),
array("id"=> "19", "name"=> "apple", "price"=> "21", "shop_id"=> "33")
)
);
Upvotes: 1