CODEWITHSUNDEEP
objective-cclosuresswift
Beanwah
Beanwah

Reputation: 1290

Working with Objective-C blocks with Swift

I'm having trouble using the Objective-C Firebase framework in a new Swift project. I'm coming from mostly a C# background so the Swift closure syntax isn't that clear yet.

Here's how the code work in Objective-C with f being the Firebase object

[f observeEventType:FEventTypeValue withBlock:^(FDataSnapshot *snapshot) {
  NSLog(@"%@ -> %@", snapshot.name, snapshot.value);
}];

XCode auto suggests this syntax, and I have yet to find a working solution.

f.observeEventType(FEventTypeValue, withBlock: ((FDataSnapshot!) -> Void)?)

I'd like assign the FDataSnapshot data to a variable as the Objective-C example is doing. Thanks

Upvotes: 11

Views: 7680

Answers (3)

David Berry
David Berry

Reputation: 41246

To throw in implied names and tail closures, you can use:

f.observeEventType(FEventTypeValue) {
    println("\($0.name) -> \($0.value)")
}

Upvotes: 4

Chuck
Chuck

Reputation: 237110

Swift blocks are interchangeable with Objective-C blocks, so it ought to be something like: 

f.observeEventType(FEventTypeValue, withBlock: { 
    snapshot in 
    println("\(snapshot.name) -> \(snapshot.value)")
})

Upvotes: 1

Jack
Jack

Reputation: 16865

Here's the Swift equivalent:

f.observeEventType(FEventTypeValue, withBlock: {
    snapshot in
    println("\(snapshot.name) -> \(snapshot.value)")
})

The key here is the in keyword to assign arguments to the closure to variables

Upvotes: 14

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