CODEWITHSUNDEEP
javascriptregex
tamersalama
tamersalama

Reputation: 4143

Javascript Regexp pattern matching

"CamelCase".replace(/[A-Z]/g, " $1")

Produces

>>" $1amel $1ase"

How to replace all occurrence of camel cases.

Upvotes: 2

Views: 1641

Answers (3)

salathe
salathe

Reputation: 51970

Maybe I'm missing something obvious but the previous answers do not act on CamelCased content but rather on all occurrences of uppercase letters.

This example preserves continuous blocks of capital letters and only separates a non-uppercase-letter followed by an uppercase letter (i.e. the CamelCase).

"CamelCaseTestHTML".replace(/([^A-Z])([A-Z])/g, "$1 $2")
// Camel Case Test HTML

Upvotes: 1

Gumbo
Gumbo

Reputation: 655825

You don’t need to use a group. Use $& to reference the whole match:

"CamelCase".replace(/[A-Z]/g, " $&")

And when using /(?!^)[A-Z]/g instead, you won’t get that leading space:

"CamelCase".replace(/(?!^)[A-Z]/g, " $&") === "Camel Case"

Upvotes: 2

YOU
YOU

Reputation: 123937

You need bracket ( ) for grouping

"CamelCase".replace(/([A-Z])/g, " $1")

produces

 Camel Case

Upvotes: 2

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