CODEWITHSUNDEEP
pythonlistcsvnested-loops
kungfool
kungfool

Reputation: 7

How to quit loop to display selected list items

I am slightly stuck on my code. My knowledge of python is very limited but I am trying to quit the loop to display the items someone selects. I have tried if statements that don't work. Considered a def statement but not too sure how to implement it and Return is an idea but obviously needs the def statement to work.

Any help is much appreciated.

P.S I have no idea how to upload the CSV file but, the following link is what I am aiming to do: https://dl.dropboxusercontent.com/u/31895483/teaching%20delivered/FE/2013-14/Access%20-%20Prg/assignment/menu2.swf

import csv

f = open("menu.csv", "r")       #Has items for the menu and is read only

spent = 0

order = []

menu = []

for line in f:

        line = line.rstrip("\n")

        dish = line.split(',')

        menu = menu + [dish]
f.close()

                       #Menu imported into python, no need to leave file open
while True:

    dishes = -1

    for dish in menu:

        if dishes == -1:
                print ("Dish No".ljust(10), end="")
        else:
                print(str(dishes).ljust(10), end="")
        print(dish[0].ljust(15), end="")
        print(dish[1].ljust(30), end="")
        print(dish[2].ljust(15), end="")
        print(dish[3], end="\n\n")
        dishes += 1
    reply = input("Please choose your first item: ")
    print()
    spent = spent + float(menu[int(reply)+1][2])
    order = order + [reply]
    print(len(order), "choices made so far =", order, "and cost = £ ", spent)
    print()
    print ("Please choose an item from the menu (0-9 or press Q to end): ")
    print()

Upvotes: 0

Views: 68

Answers (2)

Henry Keiter
Henry Keiter

Reputation: 17168

All you need to do is check for the exit condition, and then use the break statement to break out of the loop.

while True:
    # other stuff here

    reply = input("Please choose a menu item:")
    if reply.upper() == 'Q':
        break # Break out of the while loop.

    # We didn't break, so now we can try to parse the input to an integer.
    spent = spent + float(menu[int(reply)+1][2])

This pattern of while True + other_code + if condition: break is pretty common, which has at least two benefits:

  1. You're using accepted idioms, so you'll recognize them when you encounter them elsewhere.
  2. Other people (including your future self) will be able to understand your code when they read it.

Upvotes: 2

Joran Beasley
Joran Beasley

Reputation: 113988

a cool trick that I like

my_menu_choices = iter(lambda : input("Please choose a menu item:").lower(),"q")
for i,dish in dishes:
   print("%d. %s"%(i,dish))
print("Q. type q to QUIT")
my_menu_choices = list(my_menu_choices)
print("You Choose: %s"%my_menu_choices)

Upvotes: 0

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